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- Determine the scalar equation of the plane that is perpendicular to x+2y-z+10=0 and goes through the point (7,5,2)Find the scalar equation of a plane through the points (−5,−2,−4), (−6,4,1), and (1,−4,2):The scalar equation of the plane with normal vector [4, -1, 9] and passing through the point (2, -1, -1) is: a. 4x - y + 9z = 0 b. 4x - y + 9z + 7 = 0 c. 4x + y + 9z = 0 d. 4x - y - 9z = 0
- Find the equation of the plane in xyz-space through the point P=(3,3,2) and perpendicular to the vector n=(−2,1,5).Find a scalar equation of the plane that contains the points (−1, −3, 1), (1, 0, 3), and (2, 7, 0).Find the general equation of the plane through the point (3, 2, 5) that is parallel to the plane whose general equation is 2x + 3y -z = 0.