Find the terminal speed of the spherical bacterium in meters per second, ignoring the buoyant force on the bacterium and assuming Stokes' law for the viscous force. You will first need to note that the drag force is equal to the weight at terminal velocity. Take the density of the bacterium to be 1.2 × 10³ kg/m³. The viscosity of water at 20 °C is 1.002 x 103 kg/m-s and the density is 998 kg/m³. y =

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Chapter5: Further Applications Of Newton's Laws: Friction, Drag, And Elasticity
Section: Chapter Questions
Problem 27PE: Find the terminal velocity of a spherical bacterium (diameter 2.00 pm) falling in water. You will...
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Consider a spherical bacterium, with radius 1.85 um, falling in water at 20° C.
▷ A Find the terminal speed of the spherical bacterium in meters per second, ignoring the buoyant force on the bacterium and assuming Stokes' law for the
viscous force. You will first need to note that the drag force is equal to the weight at terminal velocity. Take the density of the bacterium to be 1.2 x 10³ kg/m³.
The viscosity of water at 20 °C is 1.002 x 10-3 kg/m-s and the density is 998 kg/m³.
y =
7
8
HOME
sin()
cotan()
cos()
asin()
atan() acotan
tan() T C
acos() E
4
6
sinh()
1
2 3
cotanh()
+
0
cosh() tanh()
Ⓒ Degrees Radians
END
CLEAR
VO BACKSPACE
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Transcribed Image Text:Consider a spherical bacterium, with radius 1.85 um, falling in water at 20° C. ▷ A Find the terminal speed of the spherical bacterium in meters per second, ignoring the buoyant force on the bacterium and assuming Stokes' law for the viscous force. You will first need to note that the drag force is equal to the weight at terminal velocity. Take the density of the bacterium to be 1.2 x 10³ kg/m³. The viscosity of water at 20 °C is 1.002 x 10-3 kg/m-s and the density is 998 kg/m³. y = 7 8 HOME sin() cotan() cos() asin() atan() acotan tan() T C acos() E 4 6 sinh() 1 2 3 cotanh() + 0 cosh() tanh() Ⓒ Degrees Radians END CLEAR VO BACKSPACE Submit Hint Feedback I give up!
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