Find the total current I, of the circuit below. IT Ic IRL R = 2 Q R = 10 Q %3D 100 V C = 180µF 50HZ. L = 33mH %3D HE ele +I

Q: Answer the question in the below image. In the following circuit find i,(1). 3A 3e O 2et 3et O 3e-2t

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Q: 9. Use superposition to find IO in the figure shown below. %3D Answer: Io = 0.27 mA 4 kQ 6 kO 6 k 4…

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Q: Q.4:- tind the Current at each Resistor- al8o fin d I,, Iz, I3, In f It To 2.5 10 10 Iz64 *エ 'It

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Q: What is the angle by which I leads V in this circuit? 221UF 300 44.2uF 50V/0° 60HZ O 26.8 degrees O…

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Q: 13. R equivalent´ We will AO R, R: Ry R. R2 BO

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Q: ) Find ilt) the and u(t) hor t>o in of Fige given below. 204 3, Su (4) A (@ Vー2F320H Figure

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Q: fimd the DIE1 Of the fallowing Sequence © (4)" sin ()u km)

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Q: C = 5µF L = 2mH i(t) 3R = 20

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Q: t = 0 20 60 30 20mH 2A At t=0 the switch is turned on. Find the current i̟ at t=5ms? ll

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Dielectric Breakdown

A dielectric is a material with low electrical conductivity and so is classified as an insulator. Dielectric materials are used to block the flow of electricity through them, allowing them to behave as an insulators. They can also be used to store electric charge or improve capacitance.Dielectrics have no free electrons for conduction because electrons are tightly bound to the nucleus. Because dielectrics contain a small number of electrons for electrical conductivity, they have a dipole. The two primary roles of dielectrics in electrical devices are insulation and electrical energy storage. An electric field polarizes the dielectric, and the polarization of the molecules allows dielectric materials to store charge.