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Find the value of the test statistic. (Use ₁-₂. Round your answer to two decimal places.) 0.88 Find the p-value. (Round your answer to four decimal places.) 1921 x Using a = 0.05, state your conclusion. The null hypothesis will not Descriptive Statistics Find the mean, standard deviation, and standard error for the driving distance (in yards) for current and new models of golf balls. (Round your answers to three decimal places.) Standard deviation Standard error 8.753 9.868 Mean Current 269.275 New 267.45 be rejected. There is not yd to yd to sufficient evidence to conclude that the population mean driving distance for the current golf ball is longer than that of the new golf ball. x Confidence intervals You may need to use the appropriate appendix table or technology to answer this question. Develop a 95% confidence interval for the population mean driving distance in yards of each model. (Round your answers to two decimal places.) Current New yd yd Develop a 95% confidence interval for the difference between the means of the two populations. Use current-new. (Round your answers to two decimal places.) -2.39 x yd to 6.04 x yd Comment on the confidence intervals.

Find the value of the test statistic. (Use ₁-₂. Round your answer to two decimal places.) 0.88 Find the p-value. (Round your answer to four decimal places.) 1921 x Using a = 0.05, state your conclusion. The null hypothesis will not Descriptive Statistics Find the mean, standard deviation, and standard error for the driving distance (in yards) for current and new models of golf balls. (Round your answers to three decimal places.) Standard deviation Standard error 8.753 9.868 Mean Current 269.275 New 267.45 be rejected. There is not yd to yd to sufficient evidence to conclude that the population mean driving distance for the current golf ball is longer than that of the new golf ball. x Confidence intervals You may need to use the appropriate appendix table or technology to answer this question. Develop a 95% confidence interval for the population mean driving distance in yards of each model. (Round your answers to two decimal places.) Current New yd yd Develop a 95% confidence interval for the difference between the means of the two populations. Use current-new. (Round your answers to two decimal places.) -2.39 x yd to 6.04 x yd Comment on the confidence intervals.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section: Chapter Questions
Problem 6SGR
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To compare the driving distances for the two balls, 40 balls of both the new and current models were subjected to distance tests. The testing was performed with a mechanical hitting machine so that any difference between the mean distances for the two models could be attributed to a difference in the two models.
  • Managerial Report
    Prepare a managerial report that investigates the effect of the new coating on driving distances of golf balls by comparing driving distances for the two models.
     
    Consider the results of the tests, with distances measured to the nearest yard, in the complete data set.
    Current New
    263 276
    260 270
    266 262
    271 265
    257 261
    282 252
    257 263
    265 288
    258 287
    269 265
    262 275
    263 267
    283 261
    262 272
    259 259
    282 282
    254 249
    271 262
    265 279
    267 265
    269 273
    286 260
    288 263
    279 279
    271 275
    274 282
    264 275
    259 270
    277 269
    274 263
    280 284
    273 249
    272 252
    262 259
    274 269
    266 262
    278 260
    273 256
    275 264
    261 278

    Solve the questions given in the image attached using this data.

Hypothesis Test Conduct a hypothesis test that Par could use to compare the driving distances of the current and new golf balls. (You may need to use the appropriate appendix table or technology to answer this question.) Formulate hypotheses that can be used to determine whether the sample data support the hypothesis that the population mean driving distance for the current golf ball is longer than that of the new golf ball. Let M₁ = population mean driving distance for the current golf ball and M₂ = population mean driving distance for the new golf ball. State the null and alternative hypotheses. (Enter != for as needed.) Ho: Mì - 1250 Ha: M1-M₂0 Find the value of the test statistic. (Use μ₁ −μ₂. Round your answer to two decimal places.) 0.88 X Find the p-value. (Round your answer to four decimal places.) .1921 X Using a = 0.05, state your conclusion. The null hypothesis will not Descriptive Statistics Find the mean, standard deviation, and standard error for the driving distance (in yards) for current and new models of golf balls. (Round your answers to three decimal places.) Mean Current 269.275 New 267.45 Confidence Intervals be rejected. There is not yd to yd to Standard deviation Standard error 8.753 9.868 sufficient evidence to conclude that the population mean driving distance for the current golf ball is longer than that of the new golf ball. You may need to use the appropriate appendix table or technology to answer this question. Develop a 95% confidence interval for the population mean driving distance in yards of each model. (Round your answers to two decimal places.) Current New yd yd Develop a 95% confidence interval for the difference between the means of the two populations. Use current - new. (Round your answers to two decimal places.) -2.39 Xyd to 6.04 Xyd Comment on the confidence intervals. The confidence intervals for the population mean driving distance overlap . The confidence interval for the difference between the means includes evidence to conclude that the mean driving distance for the current golf ball is longer than that of the new golf ball. zero. Thus, the result from the hypothesis test is confirmed by the confidence intervals. That is, there is insufficient ✓
Transcribed Image Text:Hypothesis Test Conduct a hypothesis test that Par could use to compare the driving distances of the current and new golf balls. (You may need to use the appropriate appendix table or technology to answer this question.) Formulate hypotheses that can be used to determine whether the sample data support the hypothesis that the population mean driving distance for the current golf ball is longer than that of the new golf ball. Let M₁ = population mean driving distance for the current golf ball and M₂ = population mean driving distance for the new golf ball. State the null and alternative hypotheses. (Enter != for as needed.) Ho: Mì - 1250 Ha: M1-M₂0 Find the value of the test statistic. (Use μ₁ −μ₂. Round your answer to two decimal places.) 0.88 X Find the p-value. (Round your answer to four decimal places.) .1921 X Using a = 0.05, state your conclusion. The null hypothesis will not Descriptive Statistics Find the mean, standard deviation, and standard error for the driving distance (in yards) for current and new models of golf balls. (Round your answers to three decimal places.) Mean Current 269.275 New 267.45 Confidence Intervals be rejected. There is not yd to yd to Standard deviation Standard error 8.753 9.868 sufficient evidence to conclude that the population mean driving distance for the current golf ball is longer than that of the new golf ball. You may need to use the appropriate appendix table or technology to answer this question. Develop a 95% confidence interval for the population mean driving distance in yards of each model. (Round your answers to two decimal places.) Current New yd yd Develop a 95% confidence interval for the difference between the means of the two populations. Use current - new. (Round your answers to two decimal places.) -2.39 Xyd to 6.04 Xyd Comment on the confidence intervals. The confidence intervals for the population mean driving distance overlap . The confidence interval for the difference between the means includes evidence to conclude that the mean driving distance for the current golf ball is longer than that of the new golf ball. zero. Thus, the result from the hypothesis test is confirmed by the confidence intervals. That is, there is insufficient ✓
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