Find u v, uu, |v||2, (u v)v, and u. (3v). . u = 8i + j - 3k, v = i - 4j + 3k (a) u. V (b) u. U (c) ||v||2 (d) (u.v)v (e) u. (3V)

Q: Find Do not simplify your answers. dy da 1. log;(√2x² + y) + tan(x² − 7") = sin¯'¹(x² − 1) + ½

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Q: II. Find dz Do not simplify your answers. 1. log,(√2x² + y) + tan(x − ³) = sin¹(x² - 1) +

A: We can solve this as follows:

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A: Find your answer below

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A: Given differential equation.

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A: We can find the correct answer as below.

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A: To prove that ∫1xx2-2xdx=x2-2xx+C

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A: Let's find.

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A: Topic:- linear function

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A: Note:- Since you have asked multiple question As per our policy, we will solve the first question…

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A: answer is in next step

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A: A vector perpendicular to A and B is :  C = A x B

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A: a(s, v)=s2-8(v+1)3v(s)=∫0s a(s, v) dv      =∫0s s2-8(v+1)3 dv     =s2v0s -8 (v+1)-3+1-3+10s     =s2s…

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Q: if any. Find the absolute extremum point (s) of f(x) = el-cos on [-],

A: f(x)=e1-cos xf'(x)=e1-cos x ddx(1-cos x)f'(x)==e1-cos x (sin x)f'(x)=0e1-cos x (sin x)=0e1-cos x ≠0…

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A: I have appended the formula used in the solution part.

Q: 2. Show that the series is conditionally convergent. n=2 cos(nx) √n ln n

A: Solution of the problem as follows

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A: To evaluate: limx→3x-3tan9-x2sin22x-6 Given limit is of the indeterminate form 00 at x→3

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