Engineering

Mechanical EngineeringQ&A LibraryFive Kg of water contained in a piston-cylinder assembly expands from an initial state where T1 = 400o C, P1 = 700 KPa to a final state where T2 =200o C, P2 = 300 KPa, with no significant effects of kinetic and potential energy. The accompanying provides additional data at the two states. It is claimed that the water undergoes an adiabatic process between these states, while developing work. Evaluate this claimSTATE 1 STATE 2T1 = 400o C T2 = 200O CP1 =700KPa = 7bar P2 =300KPa = 3 barv1= .4397 m3/kg v2=.7160 m3/kgu1 =2960.9 kj/kg u2=2650.7 kj/kgh1 = 3268.7 kj/kg h2=2865.5 kj/kgs1=7.6350 kj/kg * K s2=7.3115 lj/kgQuestion

Asked Dec 4, 2019

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Five Kg of water contained in a piston-cylinder assembly expands from an initial state where T_{1 }= 400^{o} C, P_{1} = 700 KPa to a final state where T_{2} =200^{o} C, P_{2} = 300 KPa, with no significant effects of kinetic and potential energy. The accompanying provides additional data at the two states. It is claimed that the water undergoes an adiabatic process between these states, while developing work. Evaluate this claim

STATE 1 STATE 2

T_{1} = 400^{o }C T_{2} = 200^{O }C

P_{1 }=700KPa = 7bar P_{2} =300KPa = 3 bar

v_{1}= .4397 m^{3}/kg v_{2}=.7160 m^{3}/kg

u_{1} =2960.9 kj/kg u_{2}=2650.7 kj/kg

h_{1} = 3268.7 kj/kg h_{2}=2865.5 kj/kg

s_{1}=7.6350 kj/kg * K s_{2}=7.3115 lj/kg

Step 1

Consider the expression of the entropy change for the system,

Step 2

Consider the value provided in the problem, s1=**7.635 Kj/kg K** and s2=**7.3115 Kj/kg K**

For the checking the claim, assume the process is adiabatic. Thus, the hea...

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