Question
Asked Sep 28, 2019
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Five standard solutions of HBr are prepared by serial dilution in which, at each stage, 10.00 mL are diluted to 120.00 mL. Given that the concentration of the most dilute solution is 3.52 × 10−6 M, determine the concentration of the original HBr stock solution.

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Expert Answer

Step 1

Five standard solutions of HBr are prepared by serial dilution in which, at each stage, 10.00 mL are diluted to 120.00 mL. Given that the concentration of the most dilute solution is 3.52 × 10−6 M, the concentration of the original HBr stock solution is to be calculated.

Step 2

The number of moles of solute remains same before the dilution and after the dilution.

Moles of solute before dilution = moles of solute after dilution
.M,V M,V
Where
Mi and M2 are Concentration of the solution before and after dilution respectively
V, and M, are Volume of the solution before and after dilution respectively
2
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Moles of solute before dilution = moles of solute after dilution .M,V M,V Where Mi and M2 are Concentration of the solution before and after dilution respectively V, and M, are Volume of the solution before and after dilution respectively 2

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Step 3

Determine the concentration before 5th stage dilution-

Final concentration of 5th solution, M5 = 3.52 × 10−6 M

Volume of the diluted solution, V5 = 120 mL...

After 4h dilution:
MIVMV
3.52x 10 M120 mL = 4.22 x 10 M
М,
10 mL
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After 4h dilution: MIVMV 3.52x 10 M120 mL = 4.22 x 10 M М, 10 mL

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