Following are the results of a field unit weight determination test performed by means of sand-cone method. If maximum dry unit weight is 20 kN/m^3, Determine: Calibrated Dry Density of Sand 1731 kg/m^3 Mass of jar + cone + sand (before use) 6.08 kg Mass of jar + cone + sand (after use) 2.86 kg Mass of moist soil from the hole 3.34 kg Volume of Sand Filling the Cone 3.50x10^-4 m^3 Oven-Drying for Water Content Determination: Mass of Moist Soil + Container 70 g Mass of Dry Soil + Container 65 g Mass of Container 24 g 1. Volume of soil in the hole in m 3. (in SCIENTIFIC notation and in 2 decimal places) 2. Field Dry Unit Weight in kN/m^3 (in 2 decimal places) 3. Relative Compaction (in PERCENTAGE form and in 2 decimal places)

Following are the results of a field unit weight determination test performed by means of sand-cone method. If maximum dry unit weight is 20 kN/m^3, Determine: Calibrated Dry Density of Sand 1731 kg/m^3 Mass of jar + cone + sand (before use) 6.08 kg Mass of jar + cone + sand (after use) 2.86 kg Mass of moist soil from the hole 3.34 kg Volume of Sand Filling the Cone 3.50x10^-4 m^3 Oven-Drying for Water Content Determination: Mass of Moist Soil + Container 70 g Mass of Dry Soil + Container 65 g Mass of Container 24 g 1. Volume of soil in the hole in m 3. (in SCIENTIFIC notation and in 2 decimal places) 2. Field Dry Unit Weight in kN/m^3 (in 2 decimal places) 3. Relative Compaction (in PERCENTAGE form and in 2 decimal places)

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter8: Stresses In A Soil Mass

Section: Chapter Questions

Problem 8.3P

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8 The following are results of a field unit weight determination test using sand cone method: Volume of hole = 0.0019 m3 Mass of moist soil from hole = 3.24 kg Water content = 12.01% Max. dry unit weight from a laboratory compaction test = 19.70 kN/m3 Determine the relative compaction, in percent. Round off to two decimal places. Hint: Relative compaction = Field dry unit weight / Max dry unit weight (lab)
The following are the results of a field unit weight determination test performed on the soil by means of the sand cone method. Calibrated dry density of Ottawa sand = 1570 kg/m3 Calibrated mass of Ottawa sand to fill the cone = 0.545 kg Mass of jar + cone + sand (before use) = 7.59 kg Mass of jar + cone + sand (after use) = 4.78 kg Mass of moist soil dug from hole = 3.007 kg Water content of moist soil = 10.2% Max dry unit weight = 19 kN/m3 Find the dry unit weight in kN/m3.
Data for field density by sand cone method: Weight of bottle + cone + sand before going to the field = 8990.5 g Weight of soil excavated from hole = 7550 g Weight of bottle + cone + sand after use = 2931 g Weight of sand required to fill the cone, Wc = 1578 g Dry unit weight of sand = 1.533 g/cm3 Moisture content = 6% 1- Calculate dry unit weight of compaction in the field.
The following are results of a field unit weight determination test using sand cone method: Volume of hole = 0.0019 m3 Mass of moist soil from hole = 3.48 kg Water content = 12.43% Max. dry unit weight from a laboratory compaction test = 19.56 kN/m3 Determine the relative compaction, in percent. Hint: Relative compaction = Field dry unit weight / Max dry unit weight (lab)
Following are the results of a field unit weight determination test performed by means of the sand cone method:• Calibrated dry unit weight of Ottawa sand = 104 lb/ft3• Weight of Ottawa sand to fill the cone = 0.258 lb• Weight of jar + cone + sand (before use) = 13.4 lb• Weight of jar + cone + sand (after use) = 6.39 lb• Weight of moist soil from hole = 7.3 lb• Moisture content of moist soil = 11.6%Determine: Dry unit weight of compaction in the field.
1.Three phases of a soil element? 2.Define volumetric relations (equation and text):e= , n=, S= 3. Define weight relations (equationand text):w=, Y= , Gs= 4. Range of values for degree of saturation? 5. Range of values for moisture content? 6. Correlation between dry unit weight and total unit weight (use w)? 7.Super equation (label each term)? 8. Unit weight of water ( English,metric)? 9. Average unit weight for medium dense sand? 10.Specific gravity for sand?
(a) Mass of jar with cone and sand (before use) = 4950 g, (b) mass of jar with cone and sand (after use) = 2280 g, (c) mass of soil from the hole = 2925 g, (d) dry density of sand = 1.48 g/cm3, (e) water content of the wet soil = 12%. Determine the dry unit weight of compacted soil.
Following are the results of a field unit-weight determination test performed on the same soil by means of the sand cone method: -Calibrated dry unit weight of Ottawa sand = 15.4019 kn/m3 -Calibrated weight of Ottawa sand to fill the cone = 5.3496 N -Weightof jar + cone + sand (before use) = 74.451 N -Weightof jar + cone + sand (after use) = 46.886 N -Weight of moist soil from hole = 29.509 N -Moisture content of moist soil = 10.21% DETERMINE AND SHOW COMPLETE SOLUTION 1. Dry density of compaction in the field in kg/cu.m.
During a subsurface exploration, an undisturbed soil sample was collected in the field using a split-spoon sampler. for laboratory evaluation. The sample has a diameter of 1.375 in. diameter, 18 in. length, and a wet weight of 1.85 lb. If the oven-dried weight was 1.5 lb and Gs = 2.74; calculate the following:(a) Wet unit weight.b) Moisture content.c) Dry unit weight.d) Void ratio.e) Degree of saturation.
A saturated soil sample has a unit weight of 19.24 KN/m3 and Gs = 2.70. Find Ydry, e, n,and w. 6 decimal places for the solution please
with figures if necessary 1. A wet sand sample has a volume of 4.64 x 10-4 m3 and weighs 8 N. After oven-drying, the weight reduces to 7.5 N. Calculate the water content, void ratio, and degree of saturation. 2. The mass of a wet sample of soil and its container is 0.33 kg. The dry mass of the soil and its container is 0.29 kg. The mass of the container is 0.06 kg and its volume is 0.15 x 10-3 m3. Determine the bulk, dry and saturated unit weights of the soil. Determine the void ratio and degree of saturation. Determine the amount of air void in the soil and the water of water required to saturate 1 m3 of the soil. 3. A sand has a natural water content of 5% and bulk unit weight of 18.0 kN/m3. The void ratios corresponding to the densest and loosest state of this soil are 0.51 and 0.87. Find the relative density and degree of saturation.
during a subsurface exploration, an undiscovered soil sample was collected from the field using a split spoon sampler for lab evaluation. the sample has a diameter of 34.9mm length of 457.2mm and a moist mass of 840g. if the oven dried mass was 680g and Gs= 2.74 calculate the ff. a.)moist unit weight b.)moisture content c.)dry unit weight d.)void ratio e.)degree of saturation