The following are results of a field unit weight determination test using sand cone method: Volume of hole = 0.0019 m3 Mass of moist soil from hole = 3.48 kg Water content = 12.43% Max. dry unit weight from a laboratory compaction test = 19.56 kN/m3 Determine the relative compaction, in percent. Hint: Relative compaction = Field dry unit weight / Max dry unit weight (lab)

The following are results of a field unit weight determination test using sand cone method: Volume of hole = 0.0019 m3 Mass of moist soil from hole = 3.48 kg Water content = 12.43% Max. dry unit weight from a laboratory compaction test = 19.56 kN/m3 Determine the relative compaction, in percent. Hint: Relative compaction = Field dry unit weight / Max dry unit weight (lab)

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter6: Soil Compaction

Section: Chapter Questions

Problem 6.7P

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Results of a standard proctor ompaction test on a silty sand are shown. PLEASE COMPLETE SOLUTION. 1) Find the maximum dry unit weight and optimum moisture content. 2) What is the moist unit weight at optimum moisture content? 3) What is the degree of saturation at optimum moisture content? Given: ?? = 2.69 4) If the required field dry unit weight is 18.5 ??/?3, what is the relative compaction? 5) What should be the range of compaction moisture contents in the field to achieve the above relative compaction? 6) If the minimum and maximum void ratios are 0.31 and 0.82, respectively, what is the relative density of compaction in the field?
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