For a certain reaction. The rate constant doubles when the temperature increases from 15 to 25 ⁰C Calculate (a) the activation energy, Ea and (b) the rate constant at 100 ⁰C taking k1 at 25 ⁰C to be 1.2 x 10-2 L/mol-s

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A: log (K2/K1) = {Ea × [ (1/T1) - (1/T2)]} ÷ 2.303R log (40k/k) =[Ea×{(1/277)-(1/298)}] ÷ 2.303×8.314…

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Q: For a certain reaction, the rate constant doubles when the temperature increases rom 15ºC to 25ºC.…

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Q: For a certain reaction, the rate constant doubles when the temperature increases from 15 ᴼC to 25 ᴼC…

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Q: 1 0.20 0.20 1.5 2 0.60 0.60 4.5 0.20 0.60 1.5 4 0.40 0.80 3.0 3.

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Q: he rate constant for reaction is 4.1 × 10−3 L/mol·s at 25 °C and       9.3 × 10−3 L/mol·s at 125…

A: ln(K2/K1) = -Ea/R (1/T2 - 1/T1)

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