For a prism with an apex angle of 60° and an index of refraction of 1.56. If an incident ray enters the prism at 35° from the surface normal, how many degrees will the exiting light ray deviate? 0₁ 2) 8=0+0-a il 12 B Here are some formulas for your reference: 1)a=0₁₁+0 12 a α 02/ n - 3) 8=0,₁+ sin−¹[(sin a) (n² — sin² 0₁₁) ¹/²_ sin 0₁₁ cos a]- a il D (0₁1-0₁₁) 102 114 (02-012)

Physics for Scientists and Engineers: Foundations and Connections
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ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter38: Refraction And Images Formed By Refraction
Section: Chapter Questions
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Question 3
For a prism with an apex angle of 60° and an index of refraction of 1.56. If an incident ray enters the prism at 35⁰
from the surface normal, how many degrees will the exiting light ray deviate?
Here are some formulas for your reference:
1)a=0₁₁+02
2) 8=0+0₁2-0
il
Show answer choices
A) 41.56°
-α
1/2
3) 6 = 0,₁ + sin−¹[(sin a) (n²-sin² 0₁₁) ¹²- sin 0₁, cos a]-a
B) 43.70⁰
C) 46.15°
(D) 48.00⁰
E) 50.83°
F) 53.21°
G) 55.27°
0₁1
H) 58.33°
None of the above.
n
(0₁1-0₁₁)
(012-012)
Transcribed Image Text:Question 3 For a prism with an apex angle of 60° and an index of refraction of 1.56. If an incident ray enters the prism at 35⁰ from the surface normal, how many degrees will the exiting light ray deviate? Here are some formulas for your reference: 1)a=0₁₁+02 2) 8=0+0₁2-0 il Show answer choices A) 41.56° -α 1/2 3) 6 = 0,₁ + sin−¹[(sin a) (n²-sin² 0₁₁) ¹²- sin 0₁, cos a]-a B) 43.70⁰ C) 46.15° (D) 48.00⁰ E) 50.83° F) 53.21° G) 55.27° 0₁1 H) 58.33° None of the above. n (0₁1-0₁₁) (012-012)
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