Determine the group classification using the AASHTO Classification System. Explain every step and criteria that you considered that lead to your final choice of classification. For a sample of soil, the following grain size characteristics are given:Sieve No.Percent Passing4102040802001009583654322.3Liquid Limit = 45Plastic Limit = 25Uniformity Coefficient = 5Coefficient of Curvature = 1.7

For a sample of soil, the following grain size characteristics are given: Sieve No. Percent Passing 4 10 20 40 80 200 100 95 83 65 43 22.3 Liquid Limit = 45 Plastic Limit = 25 Uniformity Coefficient = 5 Coefficient of Curvature = 1.7

For a sample of soil, the following grain size characteristics are given: Sieve No. Percent Passing 4 10 20 40 80 200 100 95 83 65 43 22.3 Liquid Limit = 45 Plastic Limit = 25 Uniformity Coefficient = 5 Coefficient of Curvature = 1.7

Principles of Foundation Engineering (MindTap Course List)

9th Edition

ISBN:9781337705028

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter2: Geotechnical Properties Of Soil

Section: Chapter Questions

Problem 2.23P

See similar textbooks

Similar questions

U B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30 = 0.35 mm D₁0 = 70 μm L.L = 36% P.L = 31% D8 = 2 µm 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if we = 26%.
5. The following information is obtained from a sieve analysis to determine the range of particle sizes in a granular soil sample. Sieve Size Sieve Opening (4.76) Percent Finer#4 4.76 96#10 2.00 80#20 0.84 51#40 0.42 38#60 0.25 25#100 0.149 12#200 0.074 5 Present the information as grain-size curve on semi-logarithmic coordinates of percent finer against particle size diameter. From the plot, determine the uniformity coefficient Cu.
Sr B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30=0.35 mm D₁0 = 70 μm D8=2 μm L.L = 36% P.L = 31% 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if wc = 26%.
5. The following information is obtained from a sieve analysis to determine the range of particle sizes in a granular soil sample. Sieve Size Sieve Opening (4.76) Percent Finer # 4 4.76 96 #10 2.00 80 #20 0.84 51 # 40 0.42 38 #60 0.25 25 #100 0.149 12 #200 0.074 Present the information as grain-size curve on semi-logarithmic coordinates of percent finer against particle size diameter. From the plot, determine the uniformity coefficient Cu.
The grain-size characteristics of soil re given in the following table. Use Table 2.3 for the analysis. Size (mm) Percent finer 0.425 100 0.1 79 0.04 57 0.02 48 0.01 40 0.002 35 0.001 33 Table 2.3 Particle-Size Classifications Grain size (mm) Name of organization Gravel Sand Silt Clay Massachusetts Institute of Technology (MIT) >2 2 to 0.06 0.06 to 0.002 2 <0.002 76.2 to 2 2 to 0.075 0.075 to 0.002 <0.002 Fines (i.e., silts and clays) <0.075 76.2 to 4.75 4.75 to 0.075 Note: Sieve openings of 4.75 mm are found on a U.S. No. 4 sieve; 2-mm openings on a U.S. No. 10 sieve; 0.075-mm openings on a U.S. No. 200 sieve. See Table 2.5. i.) What is the percentages of gravel, sand, silt and clay according to the MIT system. a.) Gravel – 0%; Sand – 38%; Silt – 30%; Clay – 35% b.) Gravel – 0%; Sand – 37%; Silt – 30%; Clay – 35% c.) Gravel – 0%; Sand – 36%; Silt – 30%; Clay – 35% d.) Gravel – 0%; Sand – 35%; Silt – 30%; Clay – 35% e.) None of the above
The grain-size characteristics of soil re given in the following table. Use Table 2.3 for the analysis. Size (mm) Percent finer 0.425 100 0.1 79 0.04 57 0.02 48 0.01 40 0.002 35 0.001 33 Table 2.3 Particle-Size Classifications Grain size (mm) Name of organization Gravel Sand Silt Clay Massachusetts Institute of Technology (MIT) >2 2 to 0.06 0.06 to 0.002 2 <0.002 76.2 to 2 2 to 0.075 0.075 to 0.002 <0.002 Fines (i.e., silts and clays) <0.075 76.2 to 4.75 4.75 to 0.075 Note: Sieve openings of 4.75 mm are found on a U.S. No. 4 sieve; 2-mm openings on a U.S. No. 10 sieve; 0.075-mm openings on a U.S. No. 200 sieve. See Table 2.5. What is the percentages of gravel, sand, silt and clay according to the USDA system a.) Gravel – 0%; Sand – 38%; Silt – 26%; Clay – 35% b.) Gravel – 0%; Sand – 38%; Silt – 27%; Clay – 33% c.) Gravel – 0%; Sand – 38%; Silt – 26%; Clay – 34% d.) Gravel – 0%; Sand – 38%; Silt – 27%; Clay – 35% e.) None of the above
Find the missed data and give the result of Fineness Modulus of sample soil data given below. Weight Percentage Cumulative Percentage finer Sieve retained Weight retained percentage N = (100 - C) S.NO size retained (C) Select one: (gm) (gm) O a. 7.824 1 75mm O b. 9.438 63mm O c. 8.142 3 50mm O d. 7.649 4 37.5mm 28mm 123 6.15 6.15 6 20mm 107 5.35 11.50 7 14mm 208 10.4 21.9 8 10mm 56 2.8 24.7 6.3mm 3.9 10 5.0mm 92 4.6 33.2 11 3.35mm 308 15.4 48.6 12 2.0mm 223 11.15 59.75 13 1.18mm 188 9.4 69.15 14 600µ 282 14.1 83.25 15 300µ 96 4.8 88.05 16 150µ 88 4.4 92.45 17 75µ 103 5.15 97.6 18 pan 48 2.4 100
(b) Classification tests for the determination of the particle size distribution of a soil produced the following results: Particle Size % finer (mm) 99 2.36 80 1.3 63 0.6 33 0.2 10 0.075 3 0.02 Then using cone penetrometer for Liquid Limit test, the results were recorded as follows. Cone penetration 15.9 17.7 19.1 20.3 22.5 (mm) Water 32.6 42.9 51.6 59.8 66.2 content (%) While the plastic limit test conducted for the same soil recorded as below:- Test No. 1 2 3 Wet soil 10.01 11.23 9.72 Dry soil 8.02 9.01 7.72 SKAA 1713 4 i) Plot the grain size distribution curve on the log graph that has been provided (Figure 2b). Calculate the uniformity coefficient, Cu and the coefficient of gradation, C, for the soil sample. Determine the plastic limit, the liquid limit and the plasticity index of the soil. Plot the graph to help you obtain the results (if necessary). ii) iii)
For the sieve analysis test, the following data is obtained. Draw the grain size distribution curve and classify the soil according to the Unified Soil Classification. (Given: LL=36, PL=29): D (mm) 9.5 2.4 0.599 0.295 0.152 0.075 Passing (%) 100 100 98 60 30 20 10
II. The grain size curve for soil sample is shown. 100 90 80 70 60 50 40 30 20 10 0 10 4. 5. 6. 1 Particle Size, mm. What is the effective grain size of the soil? What is the value of D60? 0.1 What is the value of the Coefficient of Gradation? 7. What is the value of the Coefficient of Uniformity? 8. What is the value of the Sorting Coefficient? Percent Finer, % 0.01
5. The following information is obtained from a sieve analysis to determine the range of particle sizes in a granular soil sample. Sieve Size Sieve Opening (4.76) Percent Finer #4 4.76 96 #10 2.00 80 #20 0.84 51 #40 0.42 38 #60 0.25 25 #100 0.149 12 #200 0.074
1. From the given soil samples below, (a) compute the effective size, uniformity coefficient, and coefficient of gradation (b) Determine the percent of gravel, sand, silt and clay of soil A using AASHTO Sieve size. 0.425 0.033 0.018 0.01 0.0062 0.0035 0.0018 0.001 Soil A Passing Finer (%) 100 90 80 70 60 50 40 35