For an invertible matrix A, prove that A and A-1 have the same eigenvectors. How are the eigenvalues of A related to the eigenvalues of A-1? Letting x be an eigenvector of A gives Ax = ix for a corresponding eigenvalue 2. Using matrix operations and the properties of inverse matrices gives which of the following Ax = ix Ax = Ax Ax = ix Ax = Ax A-1Ax = A-12x Ax/A = Ax/A A/(Ax) = A/(ax) AxA-1 = ixA-1 O(A/A)x = ixA-1 Ix = ixA-1 O(A/A)x = (A/a)x Ix = (A/1)x x = AA-1x OXAA-1 = AA-1x Ix = AA-1x x = AA-1x 1x xI - AA-1x x = ixA-1 x = AA-1x A-1x = A-1x = 1x A-1x = 1x A-1x = 1x This shows that --Select-- v is an eigenvector of A-1 with eigenvalue --Select--- ♥ -Select- Need Help? Read It 1/x

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter4: Eigenvalues And Eigenvectors
Section4.3: Eigenvalues And Eigenvectors Of N X N Matrices
Problem 24EQ
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For an invertible matrix A, prove that A and 
A−1
 have the same eigenvectors. How are the eigenvalues of A related to the eigenvalues of 
A−1?
Letting x be an eigenvector of A gives 
Ax = ?x
 for a corresponding eigenvalue ?. Using matrix operations and the properties of inverse matrices gives which of the following?
This shows that       is an eigenvector of 
A−1
 with eigenvalue 
      .
For an invertible matrix A, prove that A and A-1 have the same eigenvectors. How are the eigenvalues of A related to the eigenvalues of A-1?
Letting x be an eigenvector of A gives Ax = Ax for a corresponding eigenvalue 2. Using matrix operations and the properties of inverse matrices gives which of the following?
Ax = Ax
Ax-λx
Ax = Ax
Ax = 1x
AxA-1 = 1xA-1
= AA-1x
XI = A-1x
x = 1A-1x
Ax/A = Ax/A
A/(Ax) = A/(1x)
A-1Ax = A-12x
Ix = AA-1x
x = AA-1x
(A/A)x
= AxA-1
(A/A)x = (A/1)x
OXAA-1
Ix = 1xA-1
Ix =
(A/1)x
x = 1xA-1
x = 1A-1x
A-1x
1x
A-1x =
1x
A-1x = 1x
A-1x = 1x
This shows that
--Select--- v is an eigenvector of A-1 with eigenvalue ---Select--- v
Select-
Need Help?
Read It
1/x
1/1
Transcribed Image Text:For an invertible matrix A, prove that A and A-1 have the same eigenvectors. How are the eigenvalues of A related to the eigenvalues of A-1? Letting x be an eigenvector of A gives Ax = Ax for a corresponding eigenvalue 2. Using matrix operations and the properties of inverse matrices gives which of the following? Ax = Ax Ax-λx Ax = Ax Ax = 1x AxA-1 = 1xA-1 = AA-1x XI = A-1x x = 1A-1x Ax/A = Ax/A A/(Ax) = A/(1x) A-1Ax = A-12x Ix = AA-1x x = AA-1x (A/A)x = AxA-1 (A/A)x = (A/1)x OXAA-1 Ix = 1xA-1 Ix = (A/1)x x = 1xA-1 x = 1A-1x A-1x 1x A-1x = 1x A-1x = 1x A-1x = 1x This shows that --Select--- v is an eigenvector of A-1 with eigenvalue ---Select--- v Select- Need Help? Read It 1/x 1/1
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