For data that is not normally distributed we can't use z-scores. However, there is an equation that works on any distribution. It's called Chebyshev's formula. The formula is p=1−1k2p=1-1k2 where pp is the minimum percentage of scores that fall within kk standard deviations on both sides of the mean. Use this formula to answer the following questions. a) If you have scores and you don't know if they are normally distributed, find the minimum percentage of scores that fall within 2.1 standard deviations on both sides of the mean?    b) If you have scores that are normally distributed, find the percentage of scores that fall within 2.1 standard deviations on both sides of the mean?    c) If you have scores and you don't know if they are normally distributed, how many standard deviations on both sides of the mean do we need to go to have 29 percent of the scores?    Note: To answer part c you will need to solve the equation for k.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 14PPS
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For data that is not normally distributed we can't use z-scores. However, there is an equation that works on any distribution. It's called Chebyshev's formula. The formula is p=1−1k2p=1-1k2 where pp is the minimum percentage of scores that fall within kk standard deviations on both sides of the mean. Use this formula to answer the following questions.

a) If you have scores and you don't know if they are normally distributed, find the minimum percentage of scores that fall within 2.1 standard deviations on both sides of the mean?   

b) If you have scores that are normally distributed, find the percentage of scores that fall within 2.1 standard deviations on both sides of the mean?   

c) If you have scores and you don't know if they are normally distributed, how many standard deviations on both sides of the mean do we need to go to have 29 percent of the scores?   

Note: To answer part c you will need to solve the equation for k.

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