For each of the points labeled by comments, identify each of the assertions in the table below as either being always true, never true, or sometimes true/sometimes false. public static void mystery (int n) { // Point A while (n >- e) { i/ Point B Fill in each box of the the table below with ALWAYS, NEVER or SOMETIMES. Point A [ Select ] [ Select ] Point B Point C [ Select ]
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- Need help writing the following method: get(int id) – returns a Student, assuming that the student is either registered for the course or on the waitlist. If there is no student in the table or waitlist that has this id, get() should return null. You should go directly to slot id % m rather than iterating through all the slots. For context public class Course { public String code; public int capacity; public SLinkedList<Student>[] studentTable; public int size; public SLinkedList<Student> waitlist; public Course(String code) { this.code = code; this.studentTable = new SLinkedList[10]; this.size = 0; this.waitlist = new SLinkedList<Student>(); this.capacity = 10; } public Course(String code, int capacity) { this.code = code; this.studentTable = new SLinkedList[capacity]; this.size = 0; this.waitlist = new SLinkedList<>(); this.capacity =…Validate that the following code, which adds the methods var() and stddev() to Accumulator, computes both the mean and variance of the numbers presented as arguments to addDataValue(): public class Accumulator{ private double m; private double s; private int N; public void addDataValue(double x) { N++; s = s + 1.0 * (N-1) / N * (x - m) * (x - m); m = m + (x - m) / N; } public double mean() { return m; } public double var() { return s/(N - 1); } public double stddev() { return Math.sqrt(this.var()); }} This implementation is less susceptible to roundoff error than the straightforward implementation based on saving the sum of the squares of the numbers.What type of information does the following method return? public static void methodRankPoints(double points) int double nothing object Which statement is correct? The while loop repeats a set of code while a condition is not met. The number of iterations required of a while loop is always known before the while loop begins. The while loop repeats a set of code while a condition is met. The while loop does not require code to be added to manage iteration during each loop. Which of the following statements is true with regard to java exceptions? A try block can be followed by multiple catch blocks. A program automatically terminates immediately after a catch block is executed. Only one try/catch block is allowed in a single method. A try-catch is required in all methods.
- 7 public static int test1(int x1, int x2){ 8 9 if(x1==0){ 10 x1=10; 11 } 12 if(x2==0){ 13 x2=10 14 } 15 16 return x1*x2; 17 } 18 19 public static int test2(int x2, int x1){ 20 return x2-x1; 21 } 22 public static int input(){ //Don’t need to trace through //this method to show how it works. Just assume it pulls //the value for the user. 23 Scanner keyboard = new Scanner(new BufferedReader(new InputStreamReader(System.in))); 24 int counter=0; 25 System.out.print("Please enter an integer: "); 26 while(counter<3 && !keyboard.hasNextInt()) 27 { 28 System.out.println(); 29 String temp=keyboard.next(); 30 System.out.println(temp+" is not an integer. Please reenter an integer."); 31 counter++; 32 33 } 34 return keyboard.nextInt(); 35 } 36 37 38…Validate that the following code, which adds themethods var() and stddev() to Accumulator, computes both the mean and varianceof the numbers presented as arguments to addDataValue():public class Accumulator{ private double m; private double s; private int N; public void addDataValue(double x) { N++; s = s + 1.0 * (N-1) / N * (x - m) * (x - m); m = m + (x - m) / N; } public double mean() { return m; } public double var() { return s/(N - 1); } public double stddev() { return Math.sqrt(this.var()); }}This implementation is less susceptible to roundoff error than the straightforward implementation based on saving the sum of the squares of the numberUse the java code below and integrate additional method to: Print the minimum values of each row and of each column. public class ArrayOperations2D {public static int[] findRowMax(int[][] anArray) {int[] max = new int[anArray.length];for (int i = 0; i < anArray.length; i++) {int largest = anArray[i][0];for (int j = 0; j < anArray[i].length; j++) {if (anArray[i][j] > largest) {largest = anArray[i][j];}}max[i] = largest;}return max;}public static int[] findRowSums(int[][] anArray) {int[] rowSums = new int[anArray.length];for (int i = 0; i < anArray.length; i++) {int sum = 0;for (int j = 0; j < anArray[i].length; j++) {sum += anArray[i][j];}rowSums[i] = sum;}return rowSums;}public static int[] findColumnMax(int[][] anArray) {int[] max = new int[anArray[0].length];for (int j = 0; j < anArray[0].length; j++) {int largest = anArray[0][j];for (int i = 0; i < anArray.length; i++) {if (anArray[i][j] > largest) {largest = anArray[i][j];}}max[j] = largest;}return…
- Use the following methods trash() and takeOut() to answer questions (a) – (d). 1 public void trash (int x) 12 public int takeOut (int a, int b) 2 { int m, n; 13 { int d, e; 3 m = 0; 14 d = 42* a; 4 if (x > 0) 15 if (a > 0) 5 m = 4; 16 e = 2*b+d; 6 if (x > 5) 17 else 7 n = 3*m; 18 e = b+d; 8 else 19 return (e);} 9 n = 4*m; 10 int o = takeOut (m, n); 11 System.out.println ("o is: " + o);} (a) Draw separate graph for each trash() and takeOut() , then show the connection between them at call site, using the line numbers given on graph’s nodes. (b) Determine Caller, Callee, Callsite, Actual parameters and Formal parameters, in table. (c) Give all Coupling DU-pairs of last-defs and first-uses, in table. (d) find the values of m, n, a, d, b, e and o when x = -1 , 3 , 6 , in table.The files provided in the code editor to the right contain syntax and/or logic errors. In each case, determine and fix the problem, remove all syntax and coding errors, and run the program to ensure it works properly. public class DebugBox { private int width; private int length; private int height; public DebugBox() { length = 1; width = 1; height = 1; } public DebugBox(int width, int length, height) { width = width; length = length; height = height; } public void showData() { System.out.println("Width: + width + " Length: " + length + " Height: "+ height"); } public double getVolume() { double vol = length + wdth + height; return vol; } }How do I edit the code to correctly display the number of available burgers and the waiting customers? import java.util.Scanner;import java.util.Random; class Exam implements Runnable { private String cName = new String(""); public Exam (String cName, int x) { this.cName = cName; this.x = x; } static int x; @Override public void run() { Random r = new Random(); int randNum, j=0, avail=0; for(int i = 1; i <= this.x; i++) { randNum = (int) Math.floor(Math.random() * (this.x - 1 + 1) + 1); if (cName == "Consumer #1" || cName == "Consumer #2"){ avail = i - 1; System.out.println(cName + " of Thread #" + i + " buys 1 burger # of available burgers [" + avail + "] Customer(s) waiting [" + j++ + "]"); }else { int num = this.x * 2; avail = i - 1; for(i = 1; i <= num; i++){ System.out.println(cName…
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