For each of the polynomials below, state the degree and the number of nonzero terms, and select the options that describe the long-run behavior.a) p(z) = (x+ 5)(z – 3)(3x + 1)Degree:Number of nonzero terms:Long-run behavior:DA. As z goes to positive oo, p(z) goes to negative oo.B. As I goes to negative oo, p(z) goes to positive oo.C. As I goes to negative oo, p(z) goes to negative oo.OD. As I goes to positive oo, p(r) goes to positive oo.b) q(z) = 3.6z + 13z – 3z*Degree:Number of nonzero terms:Long-run behavior:A. As z goes to negative oo, q(z) goes to positive oo.B. As I goes to negative oo, q(x) goes to negative oo.IC. As I goes to positive oo, q(z) goes to positive o.OD. As I goes to positive oo, q(z) goes to negative oo.c) v(z) = r? – 7x² + 3xª +1Degree:Number of nonzero terms:Long-run behavior:DA. As z goes to positive oo, v(z) goes to negative oo.B. As z goes to positive oo, v(z) goes to positive oo.OC. As I goes to negative oo, v(z) goes to positive .OD. As I goes to negative oo, v(z) goes to negative oo.d) w(x) = -5z7Degree:Number of nonzero terms:Long-run behavior:DA. As I goes to negative oo, w(z) goes to positive oo.B. As z goes to positive oo, w(z) goes to positive oo.C. As I goes to positive oo, w(z) goes to negative oo.D. As I goes to negative oo, w(z) goes to negative oo.

Answered: Image /qna-images/answer/769e6c7b-ebee-4100-8279-3f0089dcc436.jpg

For each of the polynomials below, state the degree and the number of nonzero terms, and select the options that describe the long-run behavior. a) p(z) = (x+ 5)(z – 3)(3z +1) Degree: Number of nonzero terms: Long-run behavior: DA. As z goes to positive oo, p(z) goes to negative oo. OB. As z goes to negative oo, p(z) goes to positive oo. OC. As z goes to negative oo, p(z) goes to negative oo. OD. As I goes to positive oo, p(r) goes to positive oo.