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True or False
For each statement below, indicate whether you think it is True or False
- For the insert function, if the array is empty, there are no comparison operations that need to be performed and you can immediately add the new element
- Binary search can be used on an unsorted array to significantly improve its performance from O(n) to O(1)
- Because the update
algorithm depends on using linear search, its performance is O(1) in the worst case scenario - If you search for and delete an element in an unsorted array and then shift the rest of the elements to fill the hole, the worst case performance is O(n)
- If you search for and delete an element in an unsorted array and then move the last element to fill the hole, the worst case performance is O(n)
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Solved in 2 steps
- Below is the exercise for unsorted arrays. True or False: For each statement below, indicate whether you think it is True or False 3) For the insert function, if the array is empty, there are no comparison operations that need to be performed and you can immediately add the new element 5) Because the update algorithm depends on using linear search, its performance is O(1) in the worst case scenario 6) If you search for and delete an element in an unsorted array and then shift the rest of the elements to fill the hole, the worst case performance is O(n) 7) If you search for and delete an element in an unsorted array and then move the last element to fill the hole, the worst case performance is O(n)True or False For each statement below, indicate whether you think it is True or False Because the update algorithm depends on using linear search, its performance is O(1) in the worst case scenario If you search for and delete an element in an unsorted array and then shift the rest of the elements to fill the hole, the worst case performance is O(n) If you search for and delete an element in an unsorted array and then move the last element to fill the hole, the worst case performance is O(n)True or False For each statement below, indicate whether you think it is True or False. If you like, you can provide a description of your answer. 1) If you use binary search on a sorted array, the performance at worst is O(log n) 2) For the insert algorithm, if you use binary search to find the location to insert the new element, it will improve the overall performance of the algorithm to O(log n) 3) For the update algorithm in a sorted array, all you have to do is use linear or binary search to find the element you want to change, and if you find it, you only need to change it to the new value 4) Binary search can be used on an unsorted array
- True or False For each statement below, indicate whether you think it is True or False. If you use binary search on a sorted array, the performance at worst is O(log n) For the insert algorithm, if you use binary search to find the location to insert the new element, it will improve the overall performance of the algorithm to O(log n) For the update algorithm in a sorted array, all you have to do is use linear or binary search to find the element you want to change, and if you find it, you only need to change it to the new value Binary search can be used on an unsorted array Inserting elements into a sorted array is O(n) because you have to find the location to add the new element and then shift the remaining elements If the sorted array gets too large, the performance of binary search becomes O(n) For the delete algorithm, after you find the element to delete, you can make the algorithm run faster by replacing it with the last element in the array If you used binary search to…Below is how the arrays are represented ARRAY1[] = [1, 5, 6, 6, 9, 9, 9, 11, 11, 21] Here length of ARRAY1 is m. ARRAY2[] = [6, 6, 9, 11, 21, 21, 21] Here length of ARRAY2 is n. Array to be returned would be: ARRAY[] = [6, 9, 11, 21] ATTN : Further, please be reminded that you cannot use library functions to either sort and or perform the de-duplication operation. solve the problem in two ways In a separate implementation, code up a solution in such a way that your solution solves the problem with O(nlog(m)) time complexity 2 or O(mlog(n)) time complexity. Here log means to the base of 2. I’m sure you already know that the hint is to use Binary Search. In the form of sentences, as a comment in your code (at the bottom of your Solution2), you are required to suggest how can Solution2 be improved by leveraging the fact that both the arrays are already sorted. Suggest a solution so that your suggested solution can run linearly with O(m + n) time complexity. Your suggestion should be no…Select true or false for the statements below. Explain your answers if you like to receive partial credit1) Which of the following is true about searching elements in an unordered array?a. With the data is unsorted, search is O(n) because if the element you arelooking for is not there, you have to check every element in the arrayb. If you start at the end of the array and traverse to index 0, search improvesto O(log n) because you only have to look at half of the arrayc. If you get lucky with checking the first element and find it immediately, thenthe worst case performance of search improves to O(n^2)
- True or False For each statement below, indicate whether you think it is True or False. For the insert algorithm, if you use binary search to find the location to insert the new element, it will improve the overall performance of the algorithm to O(log n) For the update algorithm in a sorted array, all you have to do is use linear or binary search to find the element you want to change, and if you find it, you only need to change it to the new value Binary search can be used on an unsorted arraySelect true or false for the statements below. Explain your answers if you like to receive partial credit Select true or false for the statements below. Explain your answers if you like to receive partial credit Which of the following is true about searching elements in an unordered array? With the data is unsorted, search is O(n) because if the element you are looking for is not there, you have to check every element in the array If you start at the end of the array and traverse to index 0, search improves to O(log n) because you only have to look at half of the array If you get lucky with checking the first element and find it immediately, then the worst case performance of search improves to O(n^2) Which of the following is true about searching elements in an ordered array? You cannot use binary search on an ordered array so the performance is O(n) If there are no holes in the array and the elements are all next to each other, then the performance for search improves to…Wap Given a sorted array nums, remove the duplicates in-place such that each element appears only once and returns the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory. Clarification: Confused why the returned value is an integer but your answer is an array? Note that the input array is passed in by reference, which means a modification to the input array will be known to the caller as well. Internally you can think of this: // nums is passed in by reference. (i.e., without making a copy) int len = removeDuplicates(nums); // any modification to nums in your function would be known by the caller. // using the length returned by your function, it prints the first len elements. for (int i = 0; i < len; i++) { print(nums[i]); } Example 1: Input: nums = [1,1,2] Output: 2, nums = [1,2] Explanation: Your function should return length = 2, with the first two elements of nums being 1 and 2…
- Below is your exercise for Basic Sorts. For submitting your answers, you can either send me an updated Word document with your answers, email your answers directly, or even take a screen shot of your work on paper if you like. In all cases, email me your answers when you feel ready. Use the following array of numbers for each of the sorting tasks below: 6 2 8 1 7 5 3 4 Bubble Sort (not optimized) – show what the array looks like each time the swap operation is performedusing the bubble sort algorithm (not optimized, meaning no use of swapFlag) Selection Sort - show what the array looks like each time the swap operation is performed using the selection sort algorithm Insertion Sort – show what the array looks like at the end of each outer loop iteration of the insertion sort algorithmFollowing is the function for interpolation search. This searching algorithm estimates the position (index) of a key in array based on the elements in the first position and last position in the array, and the length of array. The array must be sorted in ascending order. Suppose array A contains the following 15 elements: A = [1, 3, 3, 10, 17, 22, 22, 22, 24, 25, 26, 27, 27, 28, 28] At first iteration, at which position (index) the element of 24 is estimated in array A? In which part of array (starting index and ending index) the searching should continue? How many iterations the searching are performed until the element of 24 is found? int InterpolationSearch(int x[], int key, int n) { int mid, min = 0, max = n-1; while(x[min] < key && x[max] > key) { mid = min + ((key-x[min])*(max-min)) / (x[max]-x[min]); if(x[mid] < key) min = mid + 1; else if(x[mid] > key) max = mid - 1; else return mid; } if…Select true or false for the statements below. Explain your answers if you like to receive partial credit 9) Which of the following is true about the Mergesort algorithm applied to an array ofnumbers that are all different?a. Memory usage is efficient because all swaps take place within the same arrayb. Performance is consistently at O(n log n) for all array scenariosc. When the partition function completes on the array, the pivot element willalways be in the exact center of the array