J .The given data shows a sieve analysis of soil samples A, B and(For Items 11-13) SITUATION. The given data shows a sieve analysis of soil samples A, B andС.С.Percent FinerASieve No. Diameter (mm)Percent FinerSieve No. Diameter (mm)BC58 10068B44.7602.3808458 10044.7608486846 100846 100522.380102.0000.8405236108888302.00036203678200.84036302478400.4200.2500.1492426704026 70180.4206018 22648 2054Characteristics of - 40 Fraction600.2502264100601000.149820 602000.0743182000.07431854Characteristics of - 40 Fraction43 52LL5221 3043LLPLPL2130Classify what type of soil is sample A using USCS Method.Classify what type of soil is sample Busing USCS Method.GCGWGPGMO swSCSPSMO OO O (For Items 11-13) SITUATION. The given data shows a sieve analysis of soil samples A, B andC.Percent FinerASieve No. Diameter (mm)BC8458 10046 10044.7608102.3802.0000.8400.4200.2500.1496852368830 782040603626 702418226410082018602000.074354Characteristics of-40 Fraction52LL43PL2130Classify what type of soil is sample B using USCS Method.O CLO MLCHMH

(For Items 11-13) SITUATION. The given data shows a sieve analysis of soil samples A, B and C. The given data shows a sieve analysis of soil samples A, Band C. Percent Finer A Percent Finer A B 84 58 100 68 46 100 52 36 88 36 30 78 24 26 70 18 22 64 Sieve No. Diameter (mm) Sieve No. Diameter (mm) C 84 58 100 46 100 C 4.760 2.380 2.000 0.840 0 420 0.250 0.149 0.074 4 4. 8 10 20 8 10 20 4.760 2380 2000 68 52 36 88 78 0.840 0.420 0.250 0.149 0.074 Characteristics of-40 Fraction 36 30 40 60 100 200 40 24 26 70 60 18 22 64 8 8 20 60 100 8 3 18 54 20 60 18 54 3 200 Characteristics of - 40 Fraction LL PL 43 52 43 52 21 30 LL 21 30 PL Classify what type of soil is sample A using USCS Method. Classify what type of soil is sample B using USCS Method. O GW O GC O GM GP SC O SP O SM O O O 0

(For Items 11-13) SITUATION. The given data shows a sieve analysis of soil samples A, B and C. The given data shows a sieve analysis of soil samples A, Band C. Percent Finer A Percent Finer A B 84 58 100 68 46 100 52 36 88 36 30 78 24 26 70 18 22 64 Sieve No. Diameter (mm) Sieve No. Diameter (mm) C 84 58 100 46 100 C 4.760 2.380 2.000 0.840 0 420 0.250 0.149 0.074 4 4. 8 10 20 8 10 20 4.760 2380 2000 68 52 36 88 78 0.840 0.420 0.250 0.149 0.074 Characteristics of-40 Fraction 36 30 40 60 100 200 40 24 26 70 60 18 22 64 8 8 20 60 100 8 3 18 54 20 60 18 54 3 200 Characteristics of - 40 Fraction LL PL 43 52 43 52 21 30 LL 21 30 PL Classify what type of soil is sample A using USCS Method. Classify what type of soil is sample B using USCS Method. O GW O GC O GM GP SC O SP O SM O O O 0

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Calculate the CEC of a 100g soil sample that was found to contain the following cations: Ca2+ = 0.12g Mg2+ = 0.024g K+ = 0.078g Al3+ = 0.027g NH4+ = 0.036g H+ = 0.002g
40.) The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 96 No. 8 2.380 80 No. 10 2.000 78 No. 20 0.840 61 No. 40 0.420 56 No. 60 0.250 48 No. 100 0.150 39 No. 200 0.075 33 Characteristics of No. 40 Fraction LL 38 PL 29 A. A-2-4(0) B. A-1-b(0) C. A-1-a(0) D. A-3(0) E. A-2-5(0)
Calculate the Gs of soil sample - Mass of empty clean pycnometer= 41.76 gm Mass of empty clean pycnometer + dry soil = 67.52 gm Mass of pycnometer + dry soil + water = 157.62 gm Mass of pycnometer + water =? Gs =? Write your comment about types of soil according to the result of Gs .
41.) The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 96 No. 8 2.380 80 No. 10 2.000 78 No. 20 0.840 61 No. 40 0.420 56 No. 60 0.250 48 No. 100 0.150 39 No. 200 0.075 33 Characteristics of No. 40 Fraction LL 37 PL 25 A. A-2-4(0) B. None of these. C. A-2-5(0) D. A-2-6(0) E. A-2-7(0)
A pycnometer test for the determination of water content of a soil sample having the Gs=2.70, yielded following data: Weight of moist soil=230.75g Weight of Pycnometer full of water=2965.20g Weight of Pycnometer+soil+water =3092.85g
The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Sieve No. Diameter Soil A 4 4.760 96 8 2.380 80 10 2.000 78 20 0.840 61 40 0.420 56 60 0.250 48 100 0.150 39 200 0.075 33 Characteristics of No. 40 Fraction LL 46 PL 31
The given data sohws a sieve analysis of a soild sample. Classify the soild using AASHTO Method. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 96 No. 8 2.380 80 No. 10 2.000 78 No.20 0.840 61 No.40 0.420 56 No. 60 0.250 48 No. 100 0.150 39 No. 200 0.075 33 Characteristics of No. 40 Fraction LL 46 PL 31
Calculate the coefficient of gradation, Cc. ? Classify the soil by AASHTO and USCS system. (LL = 30, PL = 10) ? Use this given M=Mass of soil retained in pan +∑Mass reatianed in each sieve⇒M=617 gM=Mass of soil retained in pan +∑Mass reatianed in each sieve⇒M=617 g Sieve No. Opening Size (mm) Mass retained (g) %Mass retained=MiM×100=MiM×100 %Cumulative mass retained % Finer 4 4.750 28 =28617×100%=4.54%=28617×100%=4.54% 4.54 95.46 10 2.0 42 =42617×100%=6.81%=42617×100%=6.81% 11.35 88.65 20 0.850 48 =48617×100%=7.78%=48617×100%=7.78% 19.13 80.87 40 0.425 128 =128617×100%=20.74%=128617×100%=20.74% 39.87 60.13 60 0.250 221 =221617×100%=35.82%=221617×100%=35.82% 75.69 24.31 100 0.150 86 =86617×100%=13.94%=86617×100%=13.94% 89.63 10.37 200 0.075 40 =40617×100%=6.48%=40617×100%=6.48% 96.11 3.89 Pan 24 =24617×100%=3.89%=24617×100%=3.89% 100 0 Now, to plot the GSD curve, the % finer is kept on the vertical axis and the opening size are kept on the horizontal axis -…
The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Sieve No. Diameter Percent Passing 4 4.760 100 6 2.380 91 10 2.000 88 20 0.840 76 40 0.420 55 60 0.250 50 100 0.150 47 200 0.075 46 Characteristics of No. 40 Fraction LL 50 PL 34
6. 1kg of soil sample, placed after a period of time, the moisture content from 25% to 20%, the water in the soil decreased ( ).A. 0.06kg B. 0.05kgC. 0.04kg D. 0.03kg 8. When calculating the time factor Tv, if the soil is drained on one side, H in the equation is taken as the thickness of the soil layer ( ).A. half B. double C. 2 times D. 4 times
soil mechanic. Classify the soil according to unified soil classification system USCS; if the following data is given : Passing sieve No. 200 =7% / Passing sieve No. 4 = 40% / D10= 0.18, D30= 0.69 and D60= 3/ LL-28%, Pl=19%
Calculate the CEC (m.e./100g soil) using the following given miliequivalent weights obtained from a 25g soil sample (a. Ca++= 2.23 m.e; b. Mg++=1.32 m.e.; c. Na+= 1.98 m.e.; d. K+= 1.87 m.e.; e. H+= 1.27 m.e.; f. Al+++= 0.11 m.e.; g. NH4+= 2.3 m.e.; h. NO3-= 1.5 m.e.