For P1=558 N and P2=698 N, the internal force in member DC is (assume all forces are tension)-3 m 3 m- 3 m-F3 mB*P1P2Select one:O A. 0О В. -698O C. -489O D. -209O E. -349

Answered: For P1=558 N and P2=698 N, the internal…

For P1=558 N and P2=698 N, the internal force in member DC is (assume all forces are tension) –3 m 3 m--–3m- 3m *P1 P21 Select one: O A.0 O B. -698 OC.- 489 O D. -209 O E.-349

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

Question

For P1=558 N and P2=698 N, the internal force in member DC is (assume all forces are tension)
-3 m 3 m- 3 m-
F
3 m
B
*P1
P2
Select one:
O A. 0
О В. -698
O C. -489
O D. -209
O E. -349

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