For problem on the picture. assume that the left side of the spring has a fixed end and the other side has pull force applied to it. The force applied to the spring is 3lbf. Solve for the following:a. Draw the free body diagram using the equivalent spring constantb. total deformation of the spring Problem No. 1Solve for the EquivalentSpring Constant for theGiven Spring Constant.K₁ =2KN,mSolutionK₁. K² And ks are Parallel Connection. Alsoky, ks are Parallel Connection.For 1.2 and 3 -(keq) = K + K₂ + K3= 2 + 4.5+ 1.2K₂= 4.5KN, ks. 1.2 KN, kn. 3.2KN, ks.mmm(keq), = 7.7 kN/mNet Equivalent, (ken)NeT(koq)net (keq),1₁ 1KG+(keq), (keq)₂kiFor 4 and 5 -(keq)₂ = k₁ + ks= 3.2 + 4.2(keq)₂ = 7.4 kN/m1.1.1.1(keq)nct 7.7 7.4 2.5(keq)net 1.504 kN/m4.2KNmKsK₂ke 2.5-

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For problem on the picture. assume that the left side of the spring has a fixed end and the other side has pull force applied to it. The force applied to the spring is 3lbf. Solve for the following: a. Draw the free body diagram using the equivalent spring constant b. total deformation of the spring

For problem on the picture. assume that the left side of the spring has a fixed end and the other side has pull force applied to it. The force applied to the spring is 3lbf. Solve for the following: a. Draw the free body diagram using the equivalent spring constant b. total deformation of the spring

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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