For the body shown. If point P3 is the center of mass for rod part P1-P2, and point P4 is the center of mass for rod part P3-P5, and P6 is the center of mass of the disk part. Find the mass moment of inertia around axis perpendicular to the page and passes through point P5. Given; L = 1 m, mass density of rod parts = 5 kg / m, mass density of disk = 12 Kg / m?

International Edition---engineering Mechanics: Statics, 4th Edition
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Chapter9: Moments And Products Of Inertia Of Areas
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For the body shown. If point P3 is the center of mass for rod part P1-P2, and point P4 is the center of mass for rod part P3-P5, and P6 is the center of mass of the disk part. Find the mass moment of inertia around axis perpendicular to the page and passes through point P5. Given; L = 1 m, mass density of rod parts = 5 kg / m, mass density of disk = 12 Kg / m?
For the body shown. If point P3 is the center of mass for rod part P1-P2, and point P4 is the
center of mass for rod part P3-P5, and P6 is the center of mass of the disk part.
Find the mass moment of inertia around axis perpendicular to the page and passes through
point P5.
Given ; L=1 m,
mass density of rod parts = 5 kg/m,
mass density of disk= 12 Kg/m?
LA L4
P1
P2
P3
L/2
P4
L/2
P5
0.1 m
0.3 m
Transcribed Image Text:For the body shown. If point P3 is the center of mass for rod part P1-P2, and point P4 is the center of mass for rod part P3-P5, and P6 is the center of mass of the disk part. Find the mass moment of inertia around axis perpendicular to the page and passes through point P5. Given ; L=1 m, mass density of rod parts = 5 kg/m, mass density of disk= 12 Kg/m? LA L4 P1 P2 P3 L/2 P4 L/2 P5 0.1 m 0.3 m
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