For the circuit given below, find the current through the capacitor icRI = 5 A L 30°XC20İc = 6.63 L-32.3° A .A ONone of the given answers .B Oic = 3.36 32.3° A.C Oİc = 3.3 2-45.6° A.D Oic = 3.3 245.6° A .E Oic = 6.53 2-35.3° A .F O

Answered: Image /qna-images/answer/f667eb6d-5a8b-4992-b907-8bcbf6553eab.jpg

For the circuit given below, find the current through the capacitor ic XL I = 5 A L 30e Xc 20 İc = 6.63 L-32.3° A .A O None of the given answers .B O ic = 3.36 32.3° A.C O İc = 3.3 2-45.6° A.D O ic = 3.3 245.6°A.E O ic = 6.53 2-35.3° A .FO

For the circuit given below, find the current through the capacitor ic XL I = 5 A L 30e Xc 20 İc = 6.63 L-32.3° A .A O None of the given answers .B O ic = 3.36 32.3° A.C O İc = 3.3 2-45.6° A.D O ic = 3.3 245.6°A.E O ic = 6.53 2-35.3° A .FO

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter24: Resistive-inductive-capacitive Parallel Circuits

Section: Chapter Questions

Problem 2PP

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Concept explainers

Capacitor

The capacitor is an element used to store electrical energy in the electrical field. A capacitor is a form of passive energy.

Question

For the circuit given below, find the current through the capacitor ic
R
I = 5 A L 30°
XC
20
İc = 6.63 L-32.3° A .A O
None of the given answers .B O
ic = 3.36 32.3° A.C O
İc = 3.3 2-45.6° A.D O
ic = 3.3 245.6° A .E O
ic = 6.53 2-35.3° A .F O

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