25V ° D) shetch the wave forms of Vc and ic VE (V) 0.446 of €15.6ms. [25(1-e V] 1 5t=28mA ic (mA →t -4/5.6ms 0.446e mA] 50=28mA For the circuit in Figure, composed of standard values: C R 8 +15 V (t = 0 s) 1 56 ΚΩ Lic + 0.1 µF vc -10 V Figure 1:

25V ° D) shetch the wave forms of Vc and ic VE (V) 0.446 of €15.6ms. [25(1-e V] 1 5t=28mA ic (mA →t -4/5.6ms 0.446e mA] 50=28mA For the circuit in Figure, composed of standard values: C R 8 +15 V (t = 0 s) 1 56 ΚΩ Lic + 0.1 µF vc -10 V Figure 1:

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter22: Resistive-capacitive Parallel Circuits

Section: Chapter Questions

Problem 2PP

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Question

Can you check if my answers are correct

(a) Determine the time constant of the circuit.

T = 5.6ms

(b) Write the mathematical equation for the voltage vC following the closing
of the switch.

Vc = 25(1 - e^-t/5.6ms)V

This one was tricky since I guess that 25V is considered E voltage. so I thought this would be divided by the resistor which I got Ic = 0.446e^-t/5.6ms

(d) Sketch the waveforms of vC and iC

25V
°
D) shetch the wave forms of Vc and ic
VE (V)
0.446
of
€15.6ms.
[25(1-e
V]
1
5t=28mA
ic (mA
→t
-4/5.6ms
0.446e mA]
50=28mA

For the circuit in Figure, composed of standard values:
C
R
8 +15 V
(t = 0 s)
1 56 ΚΩ
Lic
+
0.1 µF vc
-10 V
Figure 1:

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