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For the division problem, do your prep work by using the scaffold (partial products) and using partial multiplication table "up to 8". Then, check the answer. Remember you will need to take advantage of the fact that multiplying a number by 10, 100, etc simply adds zeros to the end of the number. See page 33 in section 7 for an example. 801688 Partial Multiplication Table 1 சகுன என்தன் 2 8 Scaffold Therefore, 8016 + 88 =

For the division problem, do your prep work by using the scaffold (partial products) and using partial multiplication table "up to 8". Then, check the answer. Remember you will need to take advantage of the fact that multiplying a number by 10, 100, etc simply adds zeros to the end of the number. See page 33 in section 7 for an example. 801688 Partial Multiplication Table 1 சகுன என்தன் 2 8 Scaffold Therefore, 8016 + 88 =

College Algebra
College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter7: Systems Of Equations And Inequalities
Section7.4: Partial Fractions
Problem 4SE: You are unsure if you correctly decomposed the partial fraction correctly. Explain how you could...
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For the division problem, do your prep work by using the scaffold (partial products) and using partial multiplication table "up to 8". Then, check the answer. Remember you will need to take advantage of the fact that multiplying a number by 10, 100, etc simply adds zeros to the end of the number. See page 33 in section 7 for an example. 801688 Partial Multiplication Table 1 → 2 → 4 → 8 → Scaffold ប្រក Therefore, 8016 : 88 =
Transcribed Image Text:For the division problem, do your prep work by using the scaffold (partial products) and using partial multiplication table "up to 8". Then, check the answer. Remember you will need to take advantage of the fact that multiplying a number by 10, 100, etc simply adds zeros to the end of the number. See page 33 in section 7 for an example. 801688 Partial Multiplication Table 1 → 2 → 4 → 8 → Scaffold ប្រក Therefore, 8016 : 88 =
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