- For the fig. (la) choose the correct sectional view explaining the reasons for the errors to others.
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- The inclined ladder AB supports a house painter (85 kg) at C and the weight iq = 40 K/m} of the ladder itself. Each ladder rail (t5= 4 mm) is supported by a shoe (ts= 5 mm) that is attached to the ladder rail by a bolt of diameter d = 8 mma helical compression spring with squared and ground ends is ti be made of a steel wire 79 gpa and presetting is to be used. the operation load of the spring can be considered static. If the maximum working force is 292 N and a force of 35 N is required when the spring is 30 mm longer, determine the spring constant kUnder some circumstances, when two parallel springswith constants k1 and k2 support a single mass, theeffective spring constant of the system is given byk 4k1k2/(k1 + k2). A mass weighing 20 pounds stretchesone spring 6 inches and another spring 2 inches. Thesprings are first attached to a common rigid supportand then to a metal plate. As the figure illustrates(see image), the mass is attached to the center of the plate in the distributiondouble spring. Determine the constant of theeffective spring for this system. find the equationof motion if the mass is initially released fromequilibrium position with downward speed of2 ft/sec.
- Dynamics of rigid bodies Problem 4A helical compression spring is 1o exert a force of 8.0 Ib when compressed 1o a length of 1.75 in. At a length of 1.25 in, the force must be 12.0 Ib. The spring will be installed in a machine that cycles slowly. and approximately 200 000 cycles total are expected. The tem- perature will not exceed 200°F. The spring will be installed in a hole having a diameter of 0.75 in. For this application. specify a suitable material, wire diameter. mean diameter. OD. ID. free length, solid length. number of coils, and type of end condition. Check the stress at the maximum operating load and at the solid length condition. The first of two solution procedures will be shown. The numbered steps can be used as a guide for future problems and as a Kind of algorithm for the spreadsheet approach that follows the manual solution.A spring with squared and ground ends is used for a load and deflection of 1.2 kN and 20 mm, respectively, with a spring index of 4. The wire diameter is 6 mm and the modulus of rigidity is 84 GPa. Which of the following is the active number of turns of the spring?
- PROBLEM The diameter of two pulleys are (0.3m)and (0.2m), center distance (1m).if we use open belt drive. Determine: 1- the length of V-belt (2ß = 60°). 2- the contact angle between belt and smaller pulley. 3- the horse power, if the smaller pulley turn with speed (400r.p.m) and the tension force in tight side (T1=900N), coefficient of friction ų=0.3 4- the speed of large pulley.Find the number of active coils of a No. 10 wire Helical Spring index of 7, steady load with spring rate of 46.5 lb/in. maximum allowable stress is 70 ksi. The stiffness of a spring is 98 N/mm of axial compression. Find the Joules of work to increase the compression from 60 mm to 90 mm.Hello, can you give at least 1 example problems and the solutions for equilibrium of rigid bodies. Step by step. Thanks!!!
- a free body diagram of the problemPLEASE DRAW the Free body diagram (FBD) and explain reasoning.Figure c shows a pulley system with a suspended load W of 2000 N. Calculate the following: (i) The effort force (F effort) necessary to lift and hold a load of 2000 N.(ii) The ideal mechanical advantage (IMA) for the pulley system.(iii) The ceiling force at ceiling anchor Point A.(iv) The ceiling force at anchor Point B.