For the following exercises, use the given information to find the unknown value. 26. y varies directly as the cube of x. When x = 3, then y = 5. Find y when x = 4. 30. y varies inversely with the square of x. When x = 4, then y = 3. Find y when x = 2. 32. y varies inversely with the square root of x. When x = 64, then y = 12. Find y when x = 36.

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter5: Polynomial And Rational Functions
Section5.8: Modeling Using Variation
Problem 48SE: For the following exercises, use Kepler’s Law, which states that the square of the time, T, required...
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For the following exercises, use the given information to find the unknown value.
26. y varies directly as the cube of x. When x = 3, then y = 5. Find y when x = 4.
30. y varies inversely with the square of x. When x = 4, then y = 3. Find y when x = 2.
32. y varies inversely with the square root of x. When x =
64, then y = 12. Find y when x = 36.
Transcribed Image Text:For the following exercises, use the given information to find the unknown value. 26. y varies directly as the cube of x. When x = 3, then y = 5. Find y when x = 4. 30. y varies inversely with the square of x. When x = 4, then y = 3. Find y when x = 2. 32. y varies inversely with the square root of x. When x = 64, then y = 12. Find y when x = 36.
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When y is directly proportional to x ,then , 

                                                                     y α x

     Proportionality sign can be removed by a proportionality constant. 

                                             Therefore,     y = k x,  where k is a proportionality constant. 

        Value of k can be calculated by given information about relation.

When y is inversely proportional to x, then,

                                                                     y α 1x

      Proportionality sign can be removed by a proportionality constant. 

                                             Therefore,     y = k *1x,  where k is a proportionality constant. 

       Value of k can be calculated by given information about relation.

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