For the following reaction, under which temperature circumstances (in °C) will it be product favored?A(g) + B(g) — C(s) + D(g) AH = -76.7 kJ/moleAS-210 J/K·molO It will be product-favored at temperatures below 89It will be product-favored at all temperaturesIt will be product-favored at temperatures below 364 CIt will be product-favored at temperatures above 43O It will be product-favored at temperatures below 316

When the change in gibbs free energy is negative, then the reaction is feasible which means product…

For the following reaction, under which temperature circumstances (in °C) will it be product favored? A(g) + B(g) →→→ C(s) + D(g) AH-76.7 kJ/mole AS-210 J/K-mol O It will be product-favored at temperatures below 89 O It will be product-favored at all temperatures O It will be product-favored at temperatures below 364 C O It will be product-favored at temperatures above 43 O It will be product-favored at temperatures below 316

For the following reaction, under which temperature circumstances (in °C) will it be product favored? A(g) + B(g) →→→ C(s) + D(g) AH-76.7 kJ/mole AS-210 J/K-mol O It will be product-favored at temperatures below 89 O It will be product-favored at all temperatures O It will be product-favored at temperatures below 364 C O It will be product-favored at temperatures above 43 O It will be product-favored at temperatures below 316

Chemistry

9th Edition

ISBN:9781133611097

Author:Steven S. Zumdahl

Publisher:Steven S. Zumdahl

Chapter17: Spontaneity, Entropy, And Free Energy

Section: Chapter Questions

Problem 55E: For the reaction at 298 K, 2NO2(g)N2O4(g) the values of H and S are 58.03 kJ and 176.6 J/K,...

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Nickel metal reacts with carbon monoxide to form tetra-carbonyl nickel, Ni(CO)4: Ni(s)+4CO(g)Ni(CO)4(g) This reaction is exploited in the Mond process in order to separate pure nickel from other metals. The reaction above separates nickel from impurities by dissolving it into the gas phase. Conditions are then changed so that the reaction runs in the opposite direction to recover the purified metal. (a) Predict the sign of S for the reaction as written above. (b) Use tabulated thermodynamic data to calculate H, S , and G for the reaction. (c) Find the range of temperatures at which this reaction is spontaneous in the forward direction.
For the reaction C2H2(g)+4F2(g)2CF4(g)+H2(g) S is equal to 358 J/K. Use this value and data from Appendix 4 to calculate the value of S for CF4(g).
For the reaction NO(g)+NO2(g)N2O3(g) , use tabulated thermodynamic data to calculate H and S. Then use those values to answer the following questions. (a) Is this reaction spontaneous at 25°C? Explain your answer. (b) If the reaction is not spontaneous at 25°C, will it become spontaneous at higher temperatures or lower temperatures? (c) To show that your prediction is accurate, choose a temperature that corresponds to your prediction in part (b) and calculate G . (Assume that both enthalpy and entropy are independent of temperature.)
The reaction shown below is involved in the refining of iron. (The table that follows provides all of the thermodynamic data you should need for this problem.) 2Fe2O3(s)+3C(s,graphite)4Fe(s)+3CO2(g) (a) Find H for the reaction. (b) S for the reaction above is 557.98 J/K. Find S° for Fe2O3(s). (c) Calculate G for the reaction at the standard temperature of 298 K. (There are two ways that you could do this.) (d) At what temperatures would this reaction be spontaneous? Compound Hf (kJ mol-1) S° (kJ mol-1) Gf (J mol-1 K-1) Fe2O3(s) -824.2 ? -742.2 C(s, graphite) 0 5.740 0 Fe(s) 0 27.3 0 CO2(g) -393.5 213.6 -394.4.83
Given the following data 2O3(g) 3O2(g)H = 427 kJ O2(g) 2O(g)H = 495 kJ NO(g) + O3(g) NO2(g) + O2(g)H = 199 kJ Calculate H for the reaction NO(g) + O(g) NO2(g)
Define the standard enthalpy of formation. What are standard states for elements and for compounds? Using Hess's law, illustrate why the formula Hreaction=npHf(products)nfHf(reactants) works to calculate H for a reaction.
Calculate H and G for the following reactions at 25C, using thermodynamic data from Appendix C; interpret the signs of H and G. a 2PbO(s)+N2(g)2Pb(s)+2NO(g)\ b CS2(l)+2H2O(l)CO2(g)+2H2S(g)
Thermodynamics provides a way to interpret everyday occurrences. If you live in northern climates, one common experience is that during early winter, snow falls but then melts when it hits the ground. Both the formation and the melting happen spontaneously. How can thermodynamics explain both of these seemingly opposed events?
Using enthalpies of formation (Appendix C), calculate H for the following reaction at 25C. Also calculate S for this reaction from standard entropies at 25C. Use these values to calculate G for the reaction at this temperature. COCl2(g)+H2O(l)CO2(g)+2HCl(g)
Consider the reaction N2O(g)+NO2(g)3NO(g)K=4.41019 (a) Calculate G for the reaction at 25C. (b) Calculate G f for N2O at 25C.
For the reaction at 298 K, 2NO2(g)N2O4(g) the values of H and S are 58.03 kJ and 176.6 J/K, respectively. What is the value of G at 298 K? Assuming that H and S do not depend on temperature, at what temperature is G = 0? Is G negative above or below this temperature?
Consider the reaction N2O2(g) 2NO2(g) where PNO2=0.29 atm and PN2O4=1.6. For this reaction at these conditions. G = 1000 J and G = 6000 J. Which of the following statements about this reaction is(are) true? a. The reverse reaction is spontaneous at these conditions. b. At equilibrium. PN2O4 will be greater than 1.6 atm. c. The value of K for this reaction is greater than 1. d. The maximum amount of work this reaction can produce at these conditions is 6000 J. e. The reaction is endothermic.

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