For the following system at equilibrium, H2(g) + CO2(g) = H20(g) + CO(g) the addition of H2(g) would cause (according to Le Chatelier's principle) O only more CO(g) to form. more H20(g) and CO(g) to form. no change in amounts of products or reactants. O only more CO,(g) to form. O only more H20(g) to form.

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ChapterU6: Showtime: Reversible Reactions And Chemical Equilibrium
SectionU6.4: How Favorable: Equilibrium Constank K
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For the following system at equilibrium,
H2(g) + CO2(g) = H20(g) + CO(g)
the addition of H2(g) would cause (according to Le Chatelier's
principle)
O only more CO(g) to form.
more H20(g) and CO(g) to form.
no change in amounts of products or reactants.
only more CO2(g) to form.
O only more H20(g) to form.
Transcribed Image Text:For the following system at equilibrium, H2(g) + CO2(g) = H20(g) + CO(g) the addition of H2(g) would cause (according to Le Chatelier's principle) O only more CO(g) to form. more H20(g) and CO(g) to form. no change in amounts of products or reactants. only more CO2(g) to form. O only more H20(g) to form.
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