For the half-wave rectifier circuit shown, the diode is not ideal and is modeled as an ideal voltage source of value Vf= =0.65V in series with an ideal diode. Vin= 2sin(2π10t) and R= 470Ω. What is the magnitude of the diode current at time t=60mst=60ms? 2- At what time between 0and T/4 seconds is the magnitude of the diode current equal to 2.66mA? Tis the period of Vin Enter your answer in
For the half-wave rectifier circuit shown, the diode is not ideal and is modeled as an ideal voltage source of value Vf= =0.65V in series with an ideal diode. Vin= 2sin(2π10t) and R= 470Ω. What is the magnitude of the diode current at time t=60mst=60ms? 2- At what time between 0and T/4 seconds is the magnitude of the diode current equal to 2.66mA? Tis the period of Vin Enter your answer in
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter8: Symmetrical Components
Section: Chapter Questions
Problem 8.1P
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For the half-wave rectifier circuit shown, the diode is not ideal and
is modeled as an ideal voltage source of value Vf= =0.65V in series
with an ideal diode. Vin= 2sin(2π10t) and R= 470Ω.
What is the magnitude of the diode current at time t=60mst=60ms?
2- At what time between 0and T/4 seconds is the magnitude of the diode current equal to 2.66mA? Tis the period of Vin Enter your answer in milliseconds
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