For the reaction A +2 B→ C under a given set of conditions, the initial rate is 0.130 M/s. Part A What is A[B]/At under the same conditions? O -0.0650 M/s O -0.130 M/s O -0.260 M/s O +0.260 M/s Submit Request Answer
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- The following experimental data were obtained for the reaction of \'I14* and NOf in acidic solution. NH/(aq) + NO2-(aq) — N;(g) + 2 H,O(f) INH/I (mol L1) [NO21 (mol L-1, Rate = A[NJ/At (mol L-1 s’) 0.0092 0.098 3.33 X IO"7 0.0092 0.049 1.66 X 10‘7 0.0488 0.196 3.51 X 10"6 0.0249 0.196 1.80 X 10-6 Determine the rate law for this reaction and calculate the rate constant.For a chemical reaction, the rate constant at 233.9 °C is 0.00306 s^-1, and the activation energy is 24.27 kJ mol^-1. Calculate the value of the rate constant at 326.7 °C. Report answer with 5 places past the demical point.For the reaction A (g) + B (g) + C(g) → D (g) The following data were obtained at constant temperature: trial [A], M [B], M [C], M Initial Rate, M/s 1 0.0500 0.0500 0.0100 6.25 × 10-3 2 0.1000 0.0500 0.0100 1.25 × 10-2 3 0.1000 0.1000 0.0100 5.00 × 10-2 4 0.0500 0.0500 0.0200 6.25 × 10-3 What is the order with respect to each reactant? Write the rate law. Calculate k (using, for example, trial 1 data).
- Consider the reaction A(g) + 2B(g) → 2C(g) + 2D(g) and associated that was collected at a constant temperature. Trial Initial [A] Initial [B] Initial Rate (mol/L) (mol/L) (mol/(L·min)) 1 0.125 0.200 7.25 2 0.375 0.200 21.75 3 0.250 0.400 14.50 4 0.375 0.400 21.75For the reaction 2N2O5(g) → 4NO2(g) + O2(g), the following data were collected. t (minutes) [N2O5] (mol/L) 0 1.24 × 10–2 10. 0.92 × 10–2 20. 0.68 × 10–2 30. 0.50 × 10–2 40. 0.37 × 10–2 50. 0.28 × 10–2 70. 0.15 × 10–2 The concentration N2O5 at 100 min will be approximately Question 17 options: A) 0.10 × 10–2 mol/L B) 0.01 × 10–2 mol/L C) 0.06 × 10–2 mol/L D) 0.03 × 10–2 mol/L E) none of theseGiven: A + B + C ----> Prods. Find the rate law and k (specific rate constant). [A] [B] [C] initial rate (Ms-1) exp.1 0.20 0.10 0.90 1.8 x 10-2 exp.2 0.10 0.20 0.30 3.0 x 10-3 exp.3 0.20 0.20 0.30 1.2 x 10-2 exp.4 0.20 0.20 0.10 4.0 x 10-3 rate = k[A]x[B]y[C]z
- 2. In the reaction, R→P, a run with [R]0 =2.571M, [R] is found to be 2.361M at t=59.0s. A run with [R]0 =3.137M, [R] is found to be 2.439 M at t = 1.8 min. How much R will be consumed if a run with [R]0 = 0.501 M is allowed to form P for t = 4.0 min. Express your answer in 2 DPs.b) what is the velocity of a reaction when [S] = 20 mM, where Vmax = 100 umol/mL*sec, and 4 Km = 2mM? can you show me how he got 98 umol / mL*sec, very close to Vmx, as [S]>>Km, at zero order of the kinetics. step by step pleaseFor each of the following sets of experimental data, using a spreadsheet, determine From the slope, determine the activation energy for the reaction (Ea) From the y-intercept, determine A for the reaction Determine k at 500 K Determine k at 720 K Determine k at 500 K Determine k at 210 K Experiment 2 T (K-1) k, (s-1) 363 2.75E-8 343 2.29E-8 333 2.08E-8 321 1.81E-8 296 1.32E-8 292 1.24E-8
- For the reaction 2N2O5(g) → 4NO2(g) + O2(g), the following data were collected. t (minutes) [N2O5] (mol/L) 0 1.24 × 10–2 10. 0.92 × 10–2 20. 0.68 × 10–2 30. 0.50 × 10–2 40. 0.37 × 10–2 50. 0.28 × 10–2 70. 0.15 × 10–2 The concentration of O2 at t = 10. min is Question 16 options: A) 0.32 × 10–2 mol/L B) 2.0 × 10–4 mol/L C) 0.64 × 10–2 mol/L D) 0.16 × 10–2 mol/L E) none of theseFill in the table with the correct responses. Reaction Order Integrated Rate Law Linear Plot Rate constant (k) from the linear plot Half life (t1/2) zero [a] [b] [c] [d] first [e] [f] [g] [h] second [i] [j] [k] [l] Answer bank: 1/At = kt + 1/Ao ln A vs time negative of the slope (-m) log A vs time At = -kt + Ao At/k Ao/2k y-intercept A vs time slope (m) At = kt + Ao 1/A vs t lnAt = -kt + lnAo ln2/k 1/kAoThe following is the experimental data for the rate of reaction: Q (g) + 2T (g) --> T2Q (g) in some conditions Experiment [Q](M) [T](M) V (M/second) 1 0,1 0,1 0,0125 2 0,2 0,1 0,05 3 0,1 0,2 0,1 if [Q] and [T] are changed to 0.5M each, then the reaction rate (v) at that time is?