For the reaction H2 (g) + Br2 (g) <----> 2HBr (g) Kp = 3.5 x 104 at 1496 K. What is the value of  Kp for the following reaction at 1496 K? 1) HBr(g) <---> 1/2 H2 (g) + 1/2 Br2 (g) K'p=  2) 2HBr(g) <----> H2 (g) + Br2 (g) K''p =  3) 1/2 H2  + 1/2 Br2 (g) <---> HBr(g) K'''p =

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Chapter13: Chemical Equilibrium
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Problem 6RQ: Distinguish between the terms equilibrium constant and reaction quotient. When Q = K, what does this...
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For the reaction

H2 (g) + Br2 (g) <----> 2HBr (g)

K= 3.5 x 104 at 1496 K. What is the value of  Kfor the following reaction at 1496 K?

1) HBr(g) <---> 1/2 H2 (g) + 1/2 Br2 (g)

K'p= 

2) 2HBr(g) <----> H2 (g) + Br2 (g)

K''p = 

3) 1/2 H+ 1/2 Br2 (g) <---> HBr(g)

K'''p = 

 
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