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For the reaction SbCl5(g) S SÜCI3(g) + Cl2{g). AG'F (SbCls) = -334.34 kJ/mol AG'f (SbCl3) = -301.25 kJ/mol AH'F (SbCls) = -394.34 kJ/mol AH'f (SbCl3) = -313.80 kJ/mol Calculate the value of the equilibrium constant (Kp) for this reaction at 298 K.

For the reaction SbCl5(g) S SÜCI3(g) + Cl2{g). AG'F (SbCls) = -334.34 kJ/mol AG'f (SbCl3) = -301.25 kJ/mol AH'F (SbCls) = -394.34 kJ/mol AH'f (SbCl3) = -313.80 kJ/mol Calculate the value of the equilibrium constant (Kp) for this reaction at 298 K.

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
Section: Chapter Questions
Problem 21PS: For the reaction BaCO3(s) BaO(s) + CO2(g), rG = +219.7 kJ/mol-rxn. Using this value and other data...
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Saved Help 1.38 x 10-6 1.78 x 10 6 1.58 x 10 6 None of the above 1.98 x 10-6
Transcribed Image Text:Saved Help 1.38 x 10-6 1.78 x 10 6 1.58 x 10 6 None of the above 1.98 x 10-6
For the reaction SbCi5(g) 5 SÜC13(g) + Cl2(g). AG'F (SbCls) = -334.34 kJ/mol AG'f (SbCl3) = -301.25 kJ/mol AH'F (SbCi5) = -394.34 kJ/mol AH°r (SbCl3) = -313.80 kJ/mol Calculate the value of the equilibrium constant (Kp) for this reaction at 298 K. Multiple Choice 1.38 x 10-6
Transcribed Image Text:For the reaction SbCi5(g) 5 SÜC13(g) + Cl2(g). AG'F (SbCls) = -334.34 kJ/mol AG'f (SbCl3) = -301.25 kJ/mol AH'F (SbCi5) = -394.34 kJ/mol AH°r (SbCl3) = -313.80 kJ/mol Calculate the value of the equilibrium constant (Kp) for this reaction at 298 K. Multiple Choice 1.38 x 10-6
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