For this question, let's assume that both the number of moles (0.438 mol Co(No3)2 and the mass of the solute 80.1 were not given in the question. How we calculate to get both of these figures?
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For this question, let's assume that both the number of moles (0.438 mol Co(No3)2 and the mass of the solute 80.1 were not given in the question. How we calculate to get both of these figures?
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- You are supplied with the following: / Jy word voorsien van die volgende: NaCl(Mr= 58,443 g /mol) 2.5MTris-Cl, pH 8 solution /oplossing (1 Litre) EDTA,natriumsout(Mr= 380,2g/mol) 10% sodium dodecyl sulphate solution / natriumdodecyl sulfaat oplossing Proteïnase K solution / oplossing (50 mg dissolved / opgelos in 1 ml ddH2O) You need a digestion buffer consisting of the following: / Jy moet 'n verteringsbuffer op maak wat uit die volgende bestaan: 15m M NaCl 75 mM Tris-Cl,pH 8 16 mM EDTA,pH 8 0.8% sodium sulphate / natrium dodecyl sulfaat 0,75 mg/ml proteïnase K How will you prepare 500 ml of the digestion buffer? Show all your steps and calculations. Remember to explain exactly how you will make it up.A salt solution (30% Na2CO3) weighing 1ton iscooled to 20C where the salt crystallizes asdecahydrate. What will be the crystal yield ifthe solubility is 21.5 kg anhydrous Na2CO3/100kg water? (assume that 3% of the totalsolution is lost by evaporation)Hexanoic acid was added to an immiscible biphasic solvent system, water and CCl4 at 20.0OC and the equilibrium concentrations of hexanoic acid were determined to be 3.66 g/L in H2O and 67.0 g/L in CCl4. Caluclate the distrubution coeffiecent (D2) of hexanoic acid in water with respect to CCl4.
- One litre of a saturated aqueous solution of Ag2SO4 (MW = 311.79 g mol- 1) at 25 °C is evaporated to dryness. 4.844 g of Ag2SO4 residue was produced. What is the solubility product (Ksp)?a concentrated H2SO4 has the following composition specific gravity 1.84 and purity of H2SO4 is 97 percent by weight. express in mole/LA 18 g of unknown organic sample was dissolve in 756 mL of benzene. The boiling point of benzene was increased by 3.36oC. As the first step of analysis, determine the moecular weight of the unknow sample? Kb of benzene= 2.64oC/m Bb of benzene = 80.09 oC density of benzene = 0.874 g/mL at 25 °C Answer in whole number, no units required.
- Prepare 1500mL of 0.5N H2SO4 solution with specific gravity of 1.84g/mL and assay of 97%Describe the preparation of 750 mL of 5.30 M H3PO4 from the commercial reagent that is 86% H3PO4 (w/w) and has a specific gravity of 1.71. Take ? mL the concentrated reagent and dilute to ? mL with water.Q1. Dissolved 0.273 grams of pure sodium oxalate (Na,C,O.) in distilled water and added sulfuric acid and titration the solution at 70 ° C by using 42.68 ml of KMNO, solution and has exceeded end point limits by using 1.46 ml of standard oxalic acid (H; C;O.) with 0.1024 N. Calculate the normlity of KMN0.. Note that the molecular weight of sodium oxalate (Na,C,O.) = 134 and its equivalent weight = 67
- What volume (mL) of the prepared low alcoholic elixir is needed if the prescription requires 120 mL of an alcoholic elixir with 35% v/v alcoholic strength? Low alcoholic elixir alcoholic strength: 20% Low Alcoholic ElixirCompound Orange Spirit 10mLAlcohol 100mLGlycerin 200mLSucrose 320gPurified water, qs ad 1000mL High alcoholic elixir alcoholic strength: 79% High Alcoholic ElixirCompound Orange Spirit 4mLSaccharin 3gGlycerin 200mLAlcohol, qs ad 1000mL a 30.51 mL b 119.39 mL c 89.49 mL d 30.61 mLA 100-liter empty jar was spiked with 20 mg of TCE (C2HCl3) under room temperature condition. The jar was then closed tightly. What is the concentration (in atm.) of TCE in the air at 25 C? (TCE: MW: 131.4 g/mol; TCE solubility in water (Cs) = 1100 mg/L; Pv (pure liquid at 25oC) = 10^-1.01 atm. KH = 10^1.03 L atm mol-1; KOW = 102.42). if the jar was half filled with water and half filled with air, what were the concentrations of TCE in both air and water at 25C?the answer is 133.33kPa N2, 20kPaAr, and 9.7333kPa CH4, i need solution steps and in the significant figure, thanks!