For x = 1, 2, 3 and y = 1, 2, let the joint pmf of X and Y be defined by f X,Y (x, y) = (x+y)/21 Show E(XY)

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A: Given that : μ = 75.0 ? = 12.5 n = 4 By using standard normal distribution we solve this problem.

Q: the odds against the event happening?

A: here p = probability of event  = 88/89

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Q: For x = 1, 2, 3 and y = 1, 2, let the joint pmf of X and Y be defined by f X,Y (x, y) = (x+y)/21…

A: The given joint pmf of X and Y can be described as X.       Y 1 2 P(X = x) 1 2/21 3/21 5/21 2…

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Q: - へ 2.00 1- PCス

A: Solution: Let Z  be the standard normal variable with mean 0 and standard deviation 1.  Z~N(0,1)

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