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THERE ARE 3 ALGEBRA BOOKS AND 7 GEOMETRY BOOKS ON A SHELF. 10.) In how many ways can you arrange all the books if there are no restrictions? A.) 3! B.) 7! C.) 10! D.) 12! 11.) If the books of the same subject must be placed together, how will you represent the number of permutations? A.) P = 3! - 7! B.) P = (3! - 7!) - 2! C.) P = 3! D.) P = 7! 12.) In how many ways can you arrange the 3 algebra books and 7 geometry books if they must be placed together? A.) 6 B.) 5,040 C.) 30,240 D.) 60,480|

THERE ARE 3 ALGEBRA BOOKS AND 7 GEOMETRY BOOKS ON A SHELF. 10.) In how many ways can you arrange all the books if there are no restrictions? A.) 3! B.) 7! C.) 10! D.) 12! 11.) If the books of the same subject must be placed together, how will you represent the number of permutations? A.) P = 3! - 7! B.) P = (3! - 7!) - 2! C.) P = 3! D.) P = 7! 12.) In how many ways can you arrange the 3 algebra books and 7 geometry books if they must be placed together? A.) 6 B.) 5,040 C.) 30,240 D.) 60,480|

Algebra and Trigonometry (MindTap Course List)
Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter14: Counting And Probability
Section14.CR: Chapter Review
Problem 2CC
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THERE ARE 3 ALGEBRA BOOKS AND 7 GEOMETRY BOOKS ON A SHELF. 10.) In how many ways can you arrange all the books if there are no restrictions? A.) 3! B.) 7! C.) 10! D.) 12! 11.) If the books of the same subject must be placed together, how will you represent the number of permutations? A.) P = 3! - 7! B.) P = (3! - 7!) - 2! C.) P = 3! D.) P = 7! 12.) In how many ways can you arrange the 3 algebra books and 7 geometry books if they must be placed together? A.) 6 B.) 5,040 C.) 30,240 D.) 60,480|
Transcribed Image Text:THERE ARE 3 ALGEBRA BOOKS AND 7 GEOMETRY BOOKS ON A SHELF. 10.) In how many ways can you arrange all the books if there are no restrictions? A.) 3! B.) 7! C.) 10! D.) 12! 11.) If the books of the same subject must be placed together, how will you represent the number of permutations? A.) P = 3! - 7! B.) P = (3! - 7!) - 2! C.) P = 3! D.) P = 7! 12.) In how many ways can you arrange the 3 algebra books and 7 geometry books if they must be placed together? A.) 6 B.) 5,040 C.) 30,240 D.) 60,480|
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