force(59ically(II) The crate shown in Fig. 4-60 lies on a plane tilted at anangle 0 25.0° to the horizontal, withuk0.19. (a) Determine the accelerationof the crate as it slides down the plane.(b) If the crate starts from rest 8.15 m upalong the plane from its base, what willbe the crate's speed when it reachesthe bottom of the incline?yforcerate itsameXFIGURE 4-60Crate on inclined plane.Problems 59 and 60.

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Asked Sep 25, 2019
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The crate shown in Fig. 4-60 lies on a plane tilted at an angle (theta)= 25.0 degrees to the horizontal, with (mu-of-k)= 0.19. (a) Determine the acceleration of the crate as it slides down the plane. (b) If the crate starts from rest 8.15 m up along the plane from its base, what will be the crate’s speed when it reaches the bottom of the incline? 

force
(59
ically
(II) The crate shown in Fig. 4-60 lies on a plane tilted at an
angle 0 25.0° to the horizontal, with
uk0.19. (a) Determine the acceleration
of the crate as it slides down the plane.
(b) If the crate starts from rest 8.15 m up
along the plane from its base, what will
be the crate's speed when it reaches
the bottom of the incline?
y
force
rate it
same
X
FIGURE 4-60
Crate on inclined plane.
Problems 59 and 60.
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force (59 ically (II) The crate shown in Fig. 4-60 lies on a plane tilted at an angle 0 25.0° to the horizontal, with uk0.19. (a) Determine the acceleration of the crate as it slides down the plane. (b) If the crate starts from rest 8.15 m up along the plane from its base, what will be the crate's speed when it reaches the bottom of the incline? y force rate it same X FIGURE 4-60 Crate on inclined plane. Problems 59 and 60.

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Expert Answer

Step 1

Free body diagram of the crate:

Angle 0 25
Kinetic friction constant 44 = 0.19
2
mg sin
mg cose
mg
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Angle 0 25 Kinetic friction constant 44 = 0.19 2 mg sin mg cose mg

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Step 2

Part (a): Acceleration of the crate:

By the equation of motion

..(1)
(2)
mgsin0- ma
mgcose-N- 0
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..(1) (2) mgsin0- ma mgcose-N- 0

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Step 3

By solving the e...

mgcose-N 0
N mgcose
Now, Kinetic friction
Put the value of f in equation ()
mgsine - N ma
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mgcose-N 0 N mgcose Now, Kinetic friction Put the value of f in equation () mgsine - N ma

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