Form the Ybus matrix of the given network. The given values of the lines are in impedance.
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Q: Form the Ybus matrix of the given network. The given values of the lines are in impedance.
A: Question is to form Y bus matrix From above network, Z12 =j0.51Z13 =j0.21Z23 =j0.25
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Q: 4. Construct or build the Z-bus matrix for the network shown in below fig. below by using KRON node…
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Q: The off-diagonal elements of ZBus matrix are known as driving point impedances O True O False
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Q: Determine Y-Bus and Z-Bus Matrix Given E1 and E2 equal 1.5 angle 0
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Q: j0.50 2 j0.20 j0.30
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- A small manufacturing plant is located 2 km down a transmission line, which has a series reactance of 0.5/km. The line resistance is negligible. The line voltage at the plant is 4800V(rms). and the plant consumes 120kW at 0.85 power factor lagging. Determine the voltage and power factor at the sending end of the transmission line by using (a) a complex power approach and (b) a circuit analysis approach.consider a transmission line with zl=3.346+j77.299 ohm assume that sb=100mva and vb=735kv find the per unit impedance convert the impedance using a new base of 200 mva and 345 kv(Q) A 10 mile transmission line with an impedance of (0.122+j0.849) Ω per mile is delivering 230A at 230kV and 0.8 power factor lagging. Determine: the sending end voltage the line efficiency and regulation
- a) Find the IBC load currentb) Give the VCA line voltagec) Calculate the total complex power on the transmission line.transmission line with an impedance of 35 Ω is connected to a load of impedance of 300 Ω, then the value of VSWR assuming that the line impedance is decreased by 30 % and load impedance is increased by 40%.For a given short transmission line of impedance R+jX ohms/phase, the sendingend and receiving end voltages Vs and Vr are fixed. Derive the expression for themaximum power that can be transmitted over the line.
- A 60 Hz, three-phase transmission line is 100 miles long. It has a total seriesimpedance of {35 + j120) n and a shunt admittance of j930 μsiemen. It delivers40 MW at 220 kV with 90% lagging power factor. Find the voltage at the sendingend by:(a) short line approximation(b) the nominal rr approximation(c) the nominal T approximationAlso determine the voltage regulation for the given line and the power loss.Assume the sending end voltage remains constant. Expected Answer: (a) 237.67 kV, 1.4284 MW, 8.03%; (b) 225.8 kV, 1.1642 MW, 8.67% (c) 225.10 kV, 1.5095 MW, 8.35% Pls. Provide Full Solution for thumbs upThe ABCD constants of a three-phase, 345-kV transmission line are A = D = 0.98182 + j0.0012447 B = 4.035 + j58.947 C = j0.00061137 The line delivers 400 MVA at 0.8 lagging power factor at 345 kV. Determine the sending end quantities, voltage regulation, and transmission efficiency.Estimate the distance over which a load of 15000 kW at 0·85 p.f. can be delivered by a 3-phase transmission line having conductors of steel-cored aluminum each of resistance 0·905 Ω/phase per kilometer. The voltage at the receiving end is to be 132 kV and the loss in transmission is to be 7·5% of the load.
- A balanced load of 30 MW is supplied at 132 kV, 50 Hz and 0•85 p.f. lagging by means of a transmission line. The series impedance of a single conductor is (20 + j52) ohms and the total phases-neutral admittance is 315 microsiemens. Shunt leakage may be neglected. Using the nominal T approximation, calculate the line voltage at the sending end of the line. If the load is removed and the sending end voltage remains constant, find the percentage rise in voltage at the receiving end.Question 1a) A network comprises of n buses. The voltage, current, active power, reactive power and admittance related to the k th bus are defined as Vk, Ik, Pk, Qk and Ykk. Deduce the following:i) Related load flow equationii) Gauss-Seidel algorithm for the load flow equationThe ABCD constants of a three-phase, 345-kV transmission line are:A = D = 0.98182 + j0.0012447.B = 4.035 + j58.947.C = j0.00061137.The line delivers 400 MVA at 0.8 lagging power factor at 345 kV. Determine the sending end quantities, voltage regulation, and transmission efficiency.Hint: Efficiency is equal to the ratio of active power at the receiving end to the active power at the sending end.