formation level at chainage 0 is 219 m and falls at the gradient of 1:100. Formation width is 20 m and side slopes of the road are 1:2. Considering all given information, answer the following questions. Show all calculations in the answer sheet. i) Determine the nature of earthwork to be cut or fill ii) Name the suitable volume calculation method for this problem (Trapezoidal or Prismoidal Rule?)

Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN:9781305970939
Author:Braja M. Das, Khaled Sobhan
Publisher:Braja M. Das, Khaled Sobhan
Chapter17: Subsoil Exploration
Section: Chapter Questions
Problem 17.13P
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Q2 Table Q2 shows the proposed reduced levels along the centerline of a road. The
formation level at chainage 0 is 219 m and falls at the gradient of 1:100. Formation
width is 20 m and side slopes of the road are 1:2. Considering all given information,
answer the following questions. Show all calculations in the answer sheet.
i) Determine the nature of earthwork to be cut or fill
C
ii) Name the suitable volume calculation method for this problem (Trapezoidal
or Prismoidal Rule?)
iii) Calculate the cut or
volume by the suitable method.
Table Q2
0 20 40 60 80 100
Reduced Level (m) 220 221 222 223 224 225
Chainage (m)
= H*(B + 2*m*H), FL(Chainage) = FL(0) + Chainage*Gradient
Hint: Across-section
Transcribed Image Text:Q2 Table Q2 shows the proposed reduced levels along the centerline of a road. The formation level at chainage 0 is 219 m and falls at the gradient of 1:100. Formation width is 20 m and side slopes of the road are 1:2. Considering all given information, answer the following questions. Show all calculations in the answer sheet. i) Determine the nature of earthwork to be cut or fill C ii) Name the suitable volume calculation method for this problem (Trapezoidal or Prismoidal Rule?) iii) Calculate the cut or volume by the suitable method. Table Q2 0 20 40 60 80 100 Reduced Level (m) 220 221 222 223 224 225 Chainage (m) = H*(B + 2*m*H), FL(Chainage) = FL(0) + Chainage*Gradient Hint: Across-section
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