Four-tenths kilogram (0.3 kg) of a certain gas is contained within a piston-cylinder assembly. The gas undergoes a process for which the pressure-volume relationship is PV° = constant. The initial pressure is 4 bar, the initial volume is 0.15 m³, and the final volume is 0.3 m3. The change in specific internal energy of the gas in the process is U2-U1 = -80 kJ. There are no significant changes in kinetic or potential energy. U2- U1 = -80 kJ %3D Gas PV = Constant Questions : 1) Calculate the work done by the piston, in kJ 2) Determine the net heat transfer for the process, in kJ( 3) Explain whether the system is loosing or gaining Heat and why

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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Four-tenths kilogram (0.3 kg) of a certain gas is
contained within a piston-cylinder assembly.
The gas undergoes a process for which the
pressure-volume relationship is PV° = constant.
The initial pressure is 4 bar, the initial volume is
0.15 m3, and the final volume is 0.3 m3. The
change in specific internal energy of the gas in
the process is U2-U1 = -80 kJ.
There are no significant changes in kinetic or
potential energy.
U2- U1 = -80 kJ
Gas
PVO =
Constant
Questions :
1) Calculate the work done by the piston, in kJ
2) Determine the net heat transfer for the
process, in kJ
3) Explain whether the system is loosing or
gaining Heat and why
Transcribed Image Text:Four-tenths kilogram (0.3 kg) of a certain gas is contained within a piston-cylinder assembly. The gas undergoes a process for which the pressure-volume relationship is PV° = constant. The initial pressure is 4 bar, the initial volume is 0.15 m3, and the final volume is 0.3 m3. The change in specific internal energy of the gas in the process is U2-U1 = -80 kJ. There are no significant changes in kinetic or potential energy. U2- U1 = -80 kJ Gas PVO = Constant Questions : 1) Calculate the work done by the piston, in kJ 2) Determine the net heat transfer for the process, in kJ 3) Explain whether the system is loosing or gaining Heat and why
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