From the following enthalpy changes, calculate the value of AH° for the reaction N21e) + O21g) > 2 NOe)- 4 NH3(g) + 5 02(g) → 4 NO(g) + 6 H2O(1) AH°=-1170 kJ 4 NH3(g) + 5-02(g) → 2 N2(g) + 6 H2O(1) AH° = -1530 kJ Al

Introductory Chemistry: A Foundation
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ISBN:9781285199030
Author:Steven S. Zumdahl, Donald J. DeCoste
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Chapter13: Gases
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Xe(g) + 2 F2(g) → XEF4(s)
AH° = -262 kJ
From the following enthalpy changes, calculate the value of AH° for the reaction N2e) + O2lg) >
2 NO (e)-
4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H20(1) AH°= -1170 kJ
4 NH3(g) + 5 O2{g) → 2 N2(g) + 6 H2O(1)
AH° = -1530 kJ
noloulate the value of AH° for the reaction 2 Ale + Fe2O3(s)→ 2 Fe(s) + Al2
Transcribed Image Text:Xe(g) + 2 F2(g) → XEF4(s) AH° = -262 kJ From the following enthalpy changes, calculate the value of AH° for the reaction N2e) + O2lg) > 2 NO (e)- 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H20(1) AH°= -1170 kJ 4 NH3(g) + 5 O2{g) → 2 N2(g) + 6 H2O(1) AH° = -1530 kJ noloulate the value of AH° for the reaction 2 Ale + Fe2O3(s)→ 2 Fe(s) + Al2
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