From the following heats of reaction,   I) N2(g) + 2O2(g)  à 2NO2(g)            ∆H = +67.6 kJ   II) 2NO(g) + O2(g) à 2NO2(g) ∆H = -2 kJ            calculate the heat of the reaction ,    N2(g) + O2(g)  à  2NO(g)  once flipping the second equation and changing its enthalpy sign, how do I cancel out or get rid of 202 in the first equation?

World of Chemistry
7th Edition
ISBN:9780618562763
Author:Steven S. Zumdahl
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Chapter10: Energy
Section: Chapter Questions
Problem 14A
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From the following heats of reaction,

 

  1. I) N2(g) + 2O2(g)  à 2NO2(g)            ∆H = +67.6 kJ

 

  1. II) 2NO(g) + O2(g) à 2NO2(g) ∆H = -2 kJ

 

         calculate the heat of the reaction ,    N2(g) + O2(g)  à  2NO(g)

 once flipping the second equation and changing its enthalpy sign, how do I cancel out or get rid of 202 in the first equation?

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