i only need Q 5 i dont need table Question 5:Use the magnitude and the angle to find the components of the sum.Table 2:methodmagnitudeanglex componenty componentsimulationalgebraicadditiongraphicaladdition From the given figureX- component of ldl > dye idl cos 55°dxId/ sisIl cos 55°55°dx 2 6 3dcas 55Y- Component of 1d1 → dy a l súss2 ldldy -11 sin s5°9,01For lel25Dcomponent,Tēl cos Rs°Il cos Q5°9.969 x loex 2Y- component, ey =-lel sin a5°/negative sign because theComponent is along negativeY- dirn- ५. 6५8» for2- Component, fx = -JPsin3fex)5 si, 30-2.5talong negative)}Y- component,fy-IFI Cos 30- 5 cos 30 c-4.33(along negative y)e sinRs

All the required data for d, e and f vectors is given in the figure in the question

From the given figure X- component of lal → dy idI cos 55° dx - Il cos 55° Idl sins dx 2 63 dcas 55 Y- Component of 1d1 → dy a 1d1 sinss dy 11 sin s 5° 9,01 For lel 25D x- component, lēl Tēl cos s° Il cos25° 9. 969 x lo ex 2 Y- component, ey = -lel sin a5° - ५. 6५8 negative sign because the Component is along negative Y- dirn → for IFI 2- Component, fy = -1PIsin3 fex) S sis 30 lalong negativen)} -2.5 Y - component, fy 2 - IF! Cos 30° - 5 cos 30 c-4.: 33 (along negative y) e sinds"

From the given figure X- component of lal → dy idI cos 55° dx - Il cos 55° Idl sins dx 2 63 dcas 55 Y- Component of 1d1 → dy a 1d1 sinss dy 11 sin s 5° 9,01 For lel 25D x- component, lēl Tēl cos s° Il cos25° 9. 969 x lo ex 2 Y- component, ey = -lel sin a5° - ५. 6५8 negative sign because the Component is along negative Y- dirn → for IFI 2- Component, fy = -1PIsin3 fex) S sis 30 lalong negativen)} -2.5 Y - component, fy 2 - IF! Cos 30° - 5 cos 30 c-4.: 33 (along negative y) e sinds"

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter1: Units And Measurement

Section: Chapter Questions

Problem 51P: Consider the physical quantities s,v,a, and t with dimensions [s]=L,[v]=LT1,[a]=LT2 and [t]=L ....

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