From the same stone launched upward at 19.62m/s from 29.9m above ground, what will be the duration of the stone's entire flight, from launch to landing on the ground ? A stone is launched vertically with an initial speed of 19.62 m/s from a starting height of 20.0 m above the ground. What maximum height (abovethe ground) will the stone reach?49.0 m19.6 m39.2 m39.6 m

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Description: From the same stone launched upward at 19.62m/s from 29.9m above ground, what will be the duration of the stone's entire flight, from launch to landing on the ground ? A stone is launched vertically with an initial speed of 19.62 m/s from a starting

Given The initial speed of the stone is u=19.62 m/s. The height from the ground from which the…

Answered: From the same stone launched upward at…

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter2: Motion In One Dimension

Section: Chapter Questions

Problem 2.6OQ: An arrow is shot straight up in the air at an initial speed of 15.0 m/s. After how much time is the...

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From the same stone launched upward at 19.62m/s from 29.9m above ground, what will be the duration of the stone's entire flight, from launch to landing on the ground ?

A stone is launched vertically with an initial speed of 19.62 m/s from a starting height of 20.0 m above the ground. What maximum height (above
the ground) will the stone reach?
49.0 m
19.6 m
39.2 m
39.6 m

Expert Solution

Step 1

Given

The initial speed of the stone is $u = 19.62 m / s$ .
The height from the ground from which the stone is launched is $h = 29.9 m$ .

When the stone launched upward from 29.9 m above the ground then it reaches maximum height and comes to its initial position so till that the displacement is 0 but when it comes to the ground then it covers 29.9 m. Therefore the displacement is $d = - 29.9 m$ .

By Newton's equation of motion,

$d = u t + \frac{1}{2} (- g) t^{2}$

Here, t is the time taken by the stone to reach the ground, and g is the acceleration due to gravity whose value is 9.8 m/s². It is taken as negative because to stone velocity is decreases and hence the stone retards.

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