f(x) = x4 - 6x3 + 9x2 a. Use the Leading Coefficient Test to determine the graph’s end behavior.b. Find the x-intercepts. State whether the graph crosses the x-axis, or touches the x-axis and turns around, at each intercept.c. Find the y-intercept.d. Determine whether the graph has y-axis symmetry, origin symmetry, or neither.e. If necessary, find a few additional points and graph the function. Use the maximum number of turning points to check whether it is drawn correctly.

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter4: Polynomial And Rational Functions
Section4.1: Quadratic Functions
Problem 104E
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f(x) = x4 - 6x3 + 9x2

a. Use the Leading Coefficient Test to determine the graph’s end behavior.
b. Find the x-intercepts. State whether the graph crosses the x-axis, or touches the x-axis and turns around, at each intercept.
c. Find the y-intercept.
d. Determine whether the graph has y-axis symmetry, origin symmetry, or neither.
e. If necessary, find a few additional points and graph the function. Use the maximum number of turning points to check whether it is drawn correctly.

Expert Solution
Step 1

“Since you have posted a question with multiple sub-parts, we will solve first three subparts for you. To get remaining sub-part solved please repost the complete question and mention the sub-parts to be solved.”

 

Given:

             f(x)=x4-6x3+9x2

 

Solution:

a) Use the leading coefficient test to determine the graph's end behavior:

       

Since,

                  The leading coefficient here is positive and of even degree

                 Hence, The highest degree is 4 (even) and polynomial is a positive function.

 

                        

                    

Step 2

Therefore,

               The graph rises to the left and right;

 

b) To determine:

                     The x-intercept=?

Solution:

                The x-intercept of the graph is that point at which the graph crosses or touches the x-axis.

 

Substituting y=0 and finding the values for x=?

                   So,

                              x4-6x3+9x2=0x2x2-6x+9=0x2(x2-(3+3)x+9)=0x2x2-3x-3x+9=0x2x(x-3)-3x-3=0x2(x-3)(x-3)=0x2(x-3)2=0

                      

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