Question

Asked Jan 30, 2019

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f(x+1) = 7x^2 + 3x - 1

Step 1

We have

f(x+1) = 7x^{2} + 3x -1

Step 2

Now substitute x+1 = z so x = z-1 in above equation, we get

f(z) = 7(z-1)^{2} +3(z-1) - 1

f(z) = 7(z^{2} + 1 -2z) +3z -3 -1

f(z) = 7z^{2} +7 -14z +3z - 3 - 1

f(z) = 7z^{2} -11z +3

Step 3

Now again substitute z = x in above equation, we...

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