Question
Asked Oct 25, 2019
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f(x)=2x2+3

What is the vertex?

What is the domain and range?

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Expert Answer

Step 1

vertex of the opening upward parabola.

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we have given f(x)-2x+3.and we have to find the vertex andit's domain and range. if we consider the function f(x)-2x2+3, it is parabola which is opening upward parabola again this curve cuts the x-axis, put f(x)=0 in the function f(x)-2x2+3 we get -3 or xt 2 0=2x2+3 Dx2 Dit is imaginary so the curve f(x) will not cuts the x axis now again consider the f(x)2x2+3, it cuts the y axis, put x-0 in the function f(x) we get f(x) 3 so the curve cuts the y axis at (0,3), also it is opening upward parabola so the vertex of the function f(x) will (0,3)

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Step 2

domain of the f...

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now for the domain of thefunction f(x), we know that domain is the set of all values of the independent variable such that dependent variable is defined after consi der the functi on fx)=x2+3,it defined for all values of xîR so the domain of the f(x)=R

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Math

Algebra