G) FNT 5: Groups 1-3: Path A Groups 3-6: Path B Here are the numerical results for FNT 5: A: WA = 2000 J, QA= -2000 J B: WB 1000 J, QB = -1000 J 1) For your path, briefly show how to find the work and heat between I and III. 2) Why is the work equal and opposite to heat between I and III? 3) Explain how the change in internal energy could be the same for the two processes, but the work and heat are different. Put your explanation on the board.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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G) FNT 5:
Groups 1-3: Path A
Groups 3-6: Path B
Here are the numerical results for FNT 5:
A: WA = 2000 J, QA= -2000 J
B: WB = 1000 J, QB = -1000 J
1) For
2) Why is the work equal and opposite to heat between I and III?
3) Explain how the change in internal energy could be the same for the two processes, but the work
and heat are different. Put your explanation on the board.
your path, briefly show how to find the work and heat between I and III.
Transcribed Image Text:G) FNT 5: Groups 1-3: Path A Groups 3-6: Path B Here are the numerical results for FNT 5: A: WA = 2000 J, QA= -2000 J B: WB = 1000 J, QB = -1000 J 1) For 2) Why is the work equal and opposite to heat between I and III? 3) Explain how the change in internal energy could be the same for the two processes, but the work and heat are different. Put your explanation on the board. your path, briefly show how to find the work and heat between I and III.
P[Pa x 10°]
4.0
2.0
(B)
|||
llb
5.0
V [m³ x 10-³]
lla
I
10.0
(A)
Transcribed Image Text:P[Pa x 10°] 4.0 2.0 (B) ||| llb 5.0 V [m³ x 10-³] lla I 10.0 (A)
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