Q1/ Water flow through an orifice meter at an empirical equation Re 0.35RE0 and a rate of 300*10° m/s, what will be the difference in pressure head across the meter. Note that : %3D 0.9m. Re= 5095.53 Ca= 0.61 g= 9.81m/s? p=1000 kg/m u = 1*10* kg/m.s m'=Mass flow rate G=Mass flux Re0= Reynolds number at orifice meter

Elements Of Electromagnetics
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Q1/ Water flow through an orifice meter at an empirical equation Re = 0.35RE0
and a rate of 300*10* m/s, what will be the difference in pressure head across the meter.
Note that :
%3D
-
0.9m.
Re=5095.53
Ca= 0.61
g= 9.81m/s
p=1000 kg/m
u = 1*10* kg/m.s
m'=Mass flow rate
%3D
G=Mass flux
Re0= Reynolds number at orifice meter
Transcribed Image Text:G Q1/ Water flow through an orifice meter at an empirical equation Re = 0.35RE0 and a rate of 300*10* m/s, what will be the difference in pressure head across the meter. Note that : %3D - 0.9m. Re=5095.53 Ca= 0.61 g= 9.81m/s p=1000 kg/m u = 1*10* kg/m.s m'=Mass flow rate %3D G=Mass flux Re0= Reynolds number at orifice meter
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