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- As we learned, monosubstituted cyclohexanes exist as anequilibrium mixture of two conformations having either an axial orequatorial substituent. When R = CH2CH3, Keq for this process is 23.When R = C(CH3)3, Keq for this process is 4000. Question: a.) When R = CH2CH3, which conformation is present in higherconcentration?b.) Which R shows the higher percentage of equatorial conformation atequilibrium?Write the IUPAC name of the following molecule: Gray balls represent C, white balls represent H. Do not include stereochemistry.Give name to the following as per 1993 IUPAC recommendations. CH3CH2CH=CH2
- In addition to more highly fluorinated products, fluorination of 2-methylbutane yields a mixture of compounds with the formula C5H10F2. Draw the structures of all the isomers with the formula C5H10F2 that would be produced and label with a star all the chiral centers present in their structures.For the following compounds identify and draw freehand structural isomers and/ or stereoisomers where possible. For each isomer, clearly explain what type of isomerism is being shown and how it arises. i) Br2C=CH2 ii) CH3CH2CH2CHOWhat is the degree of unsaturation and structure for C8H5NO2 ?
- Give the reagents and observations to distinguish between the following pairs of compounds CH3CH = Ch2 and CH3C≡CH CH3CHO and CH3COCH3 CH3CH2NH2 and CH3CONH23,4-Dimethylpent-1-ene has the formula CH2“CH¬CH(CH3)¬CH(CH3)2. When pure (R)-3,4-dimethylpent-1-ene is treated with hydrogen over a platinum catalyst, the product is (S)-2,3-dimethylpentane. Has the chiral center retained its configuration during this hydrogenation, or has it been inverted?Determine the DOU for the following molecules and suggest a structure for each. C5H7Br2ON