Given 12 csc (6x) Cot (6x) dx Step 2 How are these values înserted into the Cot (62) equation in order to gét the ans wer? Please explain in detail, Thanks du = -6 csc (62) dx 12 2 u (-du) csc2 (6x) cot (6x) dx = %3D = -u2 +C %3D Cot (6x) +C 2.

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Evaluate the indefinite integral by using the given substit...
Step 1
Given
12 csc- (6x) cot (6x) dx
Step 2
How are these values
înserted into the
equation in order to
get the ans wer?
Please explain in detail,
Cot (6x)
-6 csc? (62) dx
du =
Thanks
12 cscz(6x) cot l6x) dz = 2u(-du)
2 u (-du)
2.
u2
= -u2 +C
Cot (6x) +C
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Transcribed Image Text:E Q&A Q&A Library Evaluate the indefinite integral by using the given substit... Step 1 Given 12 csc- (6x) cot (6x) dx Step 2 How are these values înserted into the equation in order to get the ans wer? Please explain in detail, Cot (6x) -6 csc? (62) dx du = Thanks 12 cscz(6x) cot l6x) dz = 2u(-du) 2 u (-du) 2. u2 = -u2 +C Cot (6x) +C Was this solution helpful? Q& A Stuck on your homework? Ask a question and get an expertly curated answer in as fast as 30 minutes."
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