Question
Given
12 csc (6x) Cot (6x) dx
Step 2
How are these values
înserted into the
Cot (62)
equation in order to
gét the ans wer?
Please explain in detail,
Thanks
du =
-6 csc (62) dx
12 2 u (-du)
csc2 (6x) cot (6x) dx =
%3D
= -u2 +C
%3D
Cot (6x) +C
2.
Expand
Transcribed Image Text

Given 12 csc (6x) Cot (6x) dx Step 2 How are these values înserted into the Cot (62) equation in order to gét the ans wer? Please explain in detail, Thanks du = -6 csc (62) dx 12 2 u (-du) csc2 (6x) cot (6x) dx = %3D = -u2 +C %3D Cot (6x) +C 2.

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